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xxMikexx [17]
3 years ago
5

A child is given an initial push on a rope swing. On the first​ swing, the rope swings through an arc of 12 feet. On each succes

sive​ swing, the length of the arc is 80​% of the previous length. After 14 ​swings, what total length will the rope have​ swung? When the child stops​ swinging, what total length will the rope have​ swung?
Physics
1 answer:
marin [14]3 years ago
3 0

Answer:

After 14 swings, total length = 57.35 feet.

When the child stops swinging, Total length = 60 feet.

Explanation:

The total length of the rope after 14 swings form a geometric progression which is also known as exponential sequence.

The sum of the term in a Geometry progression is

Sₙ = a(1-rⁿ)/1-r.................(1)

Where Sₙ = sum of the nth term, a= first term, n= number of term, r= common ratio.

n=14, a= 12 feet, r=80% = 0.8.

Substituting the values above into equation(1)

S₁₄ = 12(1-0.8¹⁴)/1-0.8

S₁₄=  12(1-0.04398)/1-0.8

S₁₄=   12(0.95602)/0.2

S₁₄ = 11.47/0.2

S₁₄= 57.35 feet

∴ After 14 swings, the total length the rope will swing is = 57.35 feet.

The total length of the rope  when the child stop swinging = sum to infinity of the Geometry progression( exponential sequence).

The sum to infinity of an exponential sequence

S = a/1-r

Where a= first term= 12 feet, r= common ratio = 0.8.

∴ S= 12/1-0.8

  S= 12/0.2

  S = 60 feet

When the boy stops swinging, the total length the rope have swung = 60 feet.

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A ball thrown horizontally at 12.6 m/s from the roof of a building lands 20.0 m from the base of the building
S_A_V [24]

Answer:

1.59 seconds

12.3 meters

but if you are wise you will read the entire answer.

Explanation:

This is a good question -- if not a bit unusual. You should try and understand the details. It will come in handy.

Time

<u>Given</u>

a = 0 This is the critical point. There is no horizontal acceleration.

d = 20 m

v = 12.6 m/s

<u>Formula</u>

d = vi * t + 1/2at^2

<u>Solution</u>

Since the acceleration is 0, the formula reduces to

d = vi * t

20 = 12.6 * t

t = 20 / 12.6

t = 1.59 seconds.

It takes 1.59 seconds to hit the ground

Height of the building

<u>Givens</u>

t = 1.59 sec

vi = 0     Another critical point. The beginning speed vertically is 0

a = 9.8 m/s^2   The acceleration is vertical.

<u>Formula</u>

d = vi*t + 1/2 a t^2

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7 0
3 years ago
use the general formulas for gravitational force and centripetal force to derive the relationship between speed and orbital radi
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Answer:

v = \sqrt{\frac{GM}{r}}

Explanation:

The universal law of gravitation is defined as:

F = G\frac{Mm}{r^{2}}  (1)                

Where G is the gravitational constant, M and m are the masses of the two objects and r is the distance between them.

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Where v is the velocity and r is the orbital radius.

Replacing equation (3) in equation (2) it is gotten:

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mv^{2} = G\frac{Mm}{r}

v^{2} = G\frac{Mm}{mr}

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v = \sqrt{\frac{GM}{r}}

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8 0
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