Question

What is the oxidation number for Zn(OH)4 2-?

Answer 1

Answer:

The oxidation number for Zn = +2 and OH- = -1

Explanation:

Given:

Transition metal complex with the formula $[Zn(OH)_{4}]^{2-}$

To determine:

The oxidation state of Zn

Explanation:

The given complex is a negatively charged ion with a net charge of -2.

The hydroxyl ion (OH) is associated with an oxidation number of -1.

If 'x' is the oxidation number for Zn, then the sum of the charges is equal to the net charge on the ion

$x + 4(-1) = -2\\\\x = -2+4 = +2$

Answer 2

n has oxidation number of +2; each O has an oxidation number of -2; each H has an oxidation number of +1, leaving you with an overall net charge of -2
 Zn(OH)4= ; -2 = -4 + ?, Zn = +2 , the -4 is the charge on the 4 OH- ions