Answer:
12 liters of oxygen are released from the decomposition of the peroxide.
Explanation:
The hydrogen peroxide is decomposed by this reaction:
2 H₂O₂ (l) → 2 H₂O (l) + O₂ (g)
Molar mass H₂O₂ = 34 g/m
Moles of peroxide: 36.5 g / 34 g/m = 1.07 moles
Ratio is 2:1, so 2 moles of peroxide will be decomposed in 1 mol of oxygen (exactly the half)
1.07 moles of peroxide will be decomposed in the half of moles, 0.54 moles
Let's apply the Ideal Gases law Equation to solve the volume
1 atm . V = 0.54 mol . 0.082 .273K
V = (0.54 mol . 0.082 .273K) / 1 atm → 12L
Answer:
Increase in the concentration of the reactants (vinegar and baking soda) leads to an increase in the rate of reaction (more volume of CO2 is evolved within a shorter time)
Explanation:
The chemical reaction between baking soda and vinegar in water is shown in the chemical reaction equation below;
NaHCO3(aq) + CH3COOH(aq) ----->CO2(g) + H2O(l) + CH3COONa(aq)
The chemical name of baking soda is sodium bicarbonate (NaHCO3) while vineager is a dilute acetic acid (CH3COOH) solution. This reaction provides a very easy set up in which we can study the effect of concentration on the rate of chemical reaction.
We must have it behind our minds that increase in the concentration of reactant species increases the rate of chemical reaction. Secondly, the rate of the reaction between baking soda and vinegar can be monitored by observing the volume of CO2 evolved and how quickly it evolves from the reaction mixture.
We can now postulate a hypothesis which states that; 'increase in the concentration of the reactants (vinegar and baking soda) leads to an increase in the rate of reaction (more volume of CO2 is evolved within a shorter time).'
If we go ahead to subject this hypothesis to experimental test, it will be confirmed to be true because a greater volume of CO2 will be evolved within a shorter time as the concentration of the reactants increases.
Answer:
a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.
Explanation:
The heating curve is a curve that represents temperature (T) in the y-axis vs. added heat (Q) in the x-axis. The slope is T/Q = 1/C, where C is the heat capacity. Then, the higher the slope, the lower the heat capacity. For a constant mass, it can also represent the specific heat capacity (c).
Heats of vaporization and fusion cannot be calculated from these sections of the heating curve.
<em>Which statement below explains that?</em>
<em>a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.</em> YES.
<em>b. The specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol.</em> NO.
<em>c. The heat of vaporization of ethanol is less than the heat of fusion of ethanol.</em> NO.
<em>d. The heat of vaporization of ethanol is greater than the heat of fusion of ethanol.</em> NO.
Explanation:
this is the answer of your question .
hope it helped you
I can’t see the picture here’s what I see
