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Artemon [7]
3 years ago
5

The picture has my question

Chemistry
2 answers:
romanna [79]3 years ago
6 0
The answer is C.

Explanation: Between the chemicals equation it forwards out to the certain equation which also equals too the equation
aleksandr82 [10.1K]3 years ago
5 0

Answer:

b or c

Explanation:

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Rewrite and Balance the Equation <br> N₂ + H₂ -&gt; NH3
Mars2501 [29]

Answer:N

2

+ 3

H

2

-----> 2N

H

3

Explanation:

N

2

+

H

2

-----> N

H

3

Let us balance this equation by counting the number of atoms on both sides of the arrow.

N

2

+

H

2

-----> N

H

3

N=2 , H=2 N=1, H=3

To balance the number of N atom on Right Hand Side (RHS) , I will add one molecule of N

H

3

on RHS

N

2

+

H

2

-----> 2N

H

3

N=2 , H=2 N=2 , H= 6

To balance the number of H atoms on Left Hand Side (LHS) , I will add two molecules of

H

2

on LHS

N

2

+ 3

H

2

-----> 2N

H

3

N=2 , H=6 N=2 , H= 6

Answer link

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How can I balance this equation? ___ AlBr3 + ____ K2SO4 ---> ____ KBr + ____ Al2(SO4)3

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4 0
3 years ago
Read 2 more answers
Which of the following water solutions would likely have the highest boiling point?
Vedmedyk [2.9K]

Answer:

1m

Explanation:

4 0
3 years ago
What element is 1s2 2s22p6 3s23p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f10
skad [1K]
Answer:

Bi (Bismuth)
4 0
3 years ago
Read 2 more answers
The psychoactive drug sold as a methamphetamine - "speed" (c10h15n) - undergoes a series of reactions in the body; the net resul
Phoenix [80]

Answer: The coefficient of nitrogen in the given equation is 2.

Explanation: The reaction for the oxidation of methamphentamine with oxygen gas in the body is given by:

4C_{10}H_{15}N(s)+55O_2(g)\rightarrow 40CO_2(g)+30H_2O(l)+2N_2(g)

By Stoichiometry,

4 moles of methamphentamine reacts with 55 moles of oxygen gas to produce 40 moles of carbon dioxide gas, 30 moles of water and 2 moles of nitrogen gas.

Coefficient of C_{10}H_{15}N=4

Coefficient of O_2=55

Coefficient of CO_2=40

Coefficient of H_2O=30

Coefficient of N_2=2

Hence, the coefficient of nitrogen in the given equation is 2.

8 0
3 years ago
A 1.42-g sample of a pure compound with formula m2so4 was dissolved in water and treated with an ex- cess of aqueous calcium chl
solong [7]

The reaction between m_{2}SO_{4} with calcium chloride can be shown as-m_{2}SO_{4}+CaCl_{2}→CaSO_{4}↓+2mCl. The molecular weight of CaSO_{4} is 136.14g. The weight of sulfate ion is 96.06g. The molecular weight of m_{2}SO_{4} = (2×m + 96.06). From the reaction we can see that 1 mole of calcium chloride reacts with 1 molesm_{2}SO_{4} to produce 1 mole of calcium sulfate. Now 1.36g of calcium sulfate is equivalent to 1.36/136.14=9.989×10^{-3} moles of calcium sulfate.

Thus, 9.989×10^{-3} moles of m_{2}SO_{4} reacts in this reaction.

Let assume the atomic mass of m is x thus the molecular weight of m_{2}SO_{4} is 2x+96.

So we may write 9.989×10^{-3}× (2x+96) =1.42

Or, 2x + 96 = 142.146

Or, 2x = 46.146

Or, x = 23.073

Thus the atomic mass of m is 23.073. The atom (m) is sodium (Na).  

8 0
3 years ago
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