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3 years ago

Explain how atomic interactions determine a material to be transparent and opaque?

Physics

1 answer:

motikmotik3 years ago

7 0

Answer:

Explanation below.

Explanation:

It should be understood that transparency is caused through or by the transmission of light waves. This means that, If or when the energy known as the vibrational energy of a light wave is passed through the object, then the object appears clear, or transparent. And when or If the energy only causes vibrations in the surface before reflecting off the object, then the object will appear opaque, that is nontransparent.

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Challenge! A marshmallow is dropped from a 5-meter high pedestrian bridge and 0.83 seconds later, it lands right on the head of

WINSTONCH [101]

a₀). You know ...
       -- the object is dropped from 5 meters
   above the pavement;
         -- it falls for 0.83 second.

a₁). Without being told, you assume ...
   -- there is no air anyplace where the marshmallow travels,
   so it free-falls, with no air resistance;
   -- the event is happening on Earth,
where the acceleration of gravity is 9.81 m/s² .

b). You need to find how much LESS than 5 meters
   the marshmallow falls in 0.83 second.

c). You can use whatever equations you like.
   I'm going to use the equation for the distance an object falls in
   ' T ' seconds, in a place where the acceleration of gravity is ' G '.

d). To see how this all goes together for the solution, keep reading:

The distance that an object falls in ' T ' seconds
when it's dropped from rest is

   (1/2 G) x (T²) .

On Earth, ' G ' is roughly 9.81 m/s², so in 0.83 seconds,
such an object would fall

   (9.81 / 2) x (0.83)² = 3.38 meters .

It dropped from 5 meters above the pavement, but it
only fell 3.38 meters before something stopped it.
So it must have hit something that was

   (5.00 - 3.38) = 1.62 meters

above the pavement. That's where the head of the unsuspecting
person was as he innocently walked by and got clobbered.

7 0

3 years ago

What height would cause an object to have no gravitational potential energy

OverLord2011 [107]

The height is zero.
That means whatever place is your reference for height measurement,
the object is lying right there at that height.

5 0

3 years ago

if a car engine does 600,000 J of work over a 500m distance and the mass of the car is 250Kg then what is the final velocity of

drek231 [11]

Given that

Work = 600,000 J ,

distance(S) = 500 m ,

mass (m) = 250 Kg ,

Determine the velocity of car (v) = ?

We know that,

Work = Force × distance

=> Force = Work ÷ distance

= 600,000 ÷ 500

= 500 N .

Also Force F = m.a ; from Newtons II law

500 = 250 × a

a = 2 m/s.

Final Velocity from the given formula

V² = u² + 2.a.s

= 0 + 2 × 2 × 500

= \sqrt{2000}

v = 44.7 m/s

8 0

3 years ago

(a) A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by driving up a 32º ramp at a speed

stiks02 [169]

a) 7 buses

b) 6.8 m

Explanation:

The motion of the motorcycle is a projectile motion, so it consists of 2 independent motions:

- A uniform motion along the horizontal direction

- A uniformly accelerated motion along the vertical direction

The initial components of the velocity of the motorcycle are:

$v_x = u cos(32^{\circ})=(40.0)(cos 32^{\circ})=33.9 m/s\\v_y = u sin(32^{\circ})=(40.0)(sin 32^{\circ})=21.2 m/s$

The equation for the vertical motion of the motorcycle is

$y=h+u_y t - \frac{1}{2}gt^2$

where

y is the altitude at time t

h is the initial height

$g=9.8 m/s^2$ is the acceleration due to gravity

The bus top is at the same height of the initial ramp, so we have

$y=h$

And therefore, we can solve the equation for t, to find the time of flight:

$0=u_y t - \frac{1}{2}gt^2\\t(u_y-\frac{1}{2}gt)=0\\t=\frac{2u_y}{g}=\frac{2(21.2)}{9.8}=4.33 s$

Now we find what is the horizontal distance covered by the motorcycle in its jump, which is given by:

$d=v_x t = (33.9)(4.33)=146.8 m$

And since each bus has a length of L = 20.0 m, the number of buses that the motorcycle can clear with its jump is:

$n=\frac{d}{L}=\frac{146.8}{20}=7.34$

So, 7 buses.

In the previous problem, we saw that the total range of the motion of the motorcycle is

$d=146.8 m$

And we said that this corresponds to 7 buses.

Each bus has a length of

L = 20 m

So, the total length of 7 buses is

$L' = 7L=7(20)=140 m$

Therefore, the range of the motorcycle is greater than the length of the buses by:

$\Delta x = d-L'=146.8-140 = 6.8 m$

which means he will miss the last bus by 6.8 meters.

6 0

3 years ago

The amount of solar radiation received by Earth from the sun, known as _______________________, is greatest when the sun is dire

Natali5045456 [20]

The amount of solar radiation received by Earth from the sun, known as insolation, is greatest when the sun is directly overhead a location.

6 0

3 years ago