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3 years ago

8

The moon’s rotational period and revolution period are equal. What is the result of this? Enter your answer in the space provide

d.

1 answer:

beks73 [17]3 years ago

5 0

Answer The Moon has synchronous rotation: it's rotation period is the same as its period of revolution

Explanation:

The Moon has synchronous rotation: it's rotation period is the same as its period of revolution

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18. The orbits of planets being elliptical was one the planetary laws developed by

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It was a man named <span>Johannes Kepler. </span>

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3 years ago

Three materials, put them in order of what

Grace [21]

Answer:

it's a

Explanation:

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3 years ago

A motorcycle is following a car that is traveling at a constant speed on a straight highway. Initially, the car and the motorcyc

Artist 52 [7]

Answer:

(a) 3.807 s

(b) 145.581 m

Explanation:

Let Δt = t2 - t1 be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. We know that before the acceleration, both vehicles are travelling at a constant speed. So they would maintain a distance of 58 m prior to the acceleration.

The distance traveled by car after Δt (seconds) at $v_c = 23m/s$ speed is

$s_c = \Delta t v_c = 23\Delta t$

The distance traveled by the motorcycle after Δt (seconds) at $m_m = 23 m/s$ speed and acceleration of a = 8 m/s2 is

$s_m = \Delta t v_m + a\Delta t^2/2$

$s_m = 23\Delta t + 8\Delta t^2/2 = 23 \Delta t + 4 \Delta t^2$

We know that the motorcycle catches up to the car after Δt, so it must have covered the distance that the car travels, plus their initial distance:

$s_m = s_c + 58$

$23 \Delta t + 4 \Delta t^2 = 23\Delta t + 58$

$4 \Delta t^2 = 58$

$\Delta t^2 = 14.5$

$\Delta t = \sqrt{14.5} = 3.807s$

(b)

$s_m = 23 \Delta t + 4 \Delta t^2$

$s_m = 23*3.807 + 58 = 145.581 m$

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3 years ago

How are Newton's 3 laws related?

Allisa [31]

Answer:Newton's three laws of motion relate to each other in that they lay a foundation for the principles of things in motion, then build upon that foundation. For example, the first law of motion,...

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3 years ago

A river flows due east at 12 km/h. A boat crosses the 720 m wide river by maintaining a constant velocity of 72 mi/h due north r

zhenek [66]

Answer:

The boat will be 74 .17 meters downstream by the time it reaches the shore.

Explanation:

Consider the vector diagrams for velocity and distance shown below.

converting 72 miles per hour to km/hr

we have 72 miles per hour 72 × 1.60934 = 115.83 km/hr

The velocity vectors form a right angled triangle, and can be solved using simple trigonometric laws

$tan \theta = \frac{12}{115.873}$

$\theta = tan^{-1}( \frac{12}{115.873})=5.9126$

This is the vector angle with which the ship drifts away with respect to its northward direction.

<em>From the sketch of the displacement vectors, we can use trigonometric ratios to determine the distance the boat moves downstream.</em>

Let x be the distance the boat moves downstream.d

$sin(5.9126)=\frac{x}{720}$

$x= 720\times 5.9126$

$x=74.17m$

∴The boat will be 74 .17 meters downstream by the time it reaches the shore.

6 0

3 years ago