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3 years ago

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While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find th

e motion somewhat unpleasant. To take your mind off your stomach, you wonder about the motion of the ride. You estimate the radius of the big wheel to be 12 m, and you use your watch to find that each loop around takes 26 s.What is the magnitude of your acceleration

1 answer:

Lorico [155]3 years ago

4 0

Answer:

a = 0.701 m / s²

Explanation:

As the game is spinning the acceleration is centripetal

a = v² /r

The park system after a small period of acceleration goes at a constant speed, for which we can use the relations of the uniform motion

v = d / t

the distance of a circle is

d = 2π r

we substitute

a = (2π r / t) ² / r

a = 4 pi² r / t²

let's calculate

a = 4 pi² 12 / 26²

a = 0.701 m / s²

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Consider a thin rod of mass 3.2 kg, length 1.2 m and uniform density. The rod is pivoted at one end on a frictionless horizontal

notsponge [240]

Answer:

the angular acceleration is 9.7 rad/ $s^{2}$

Explanation:

given information:

mass of thin rod, m = 3.2 kg

the length of the rod, L = 1.2

angle, θ = 38

to find the acceleration of the rod, we can use the torque's formula as below,

τ = Iα

where

τ = torque

I = inertia

σ = acceleration

moment inertia of this rod, I

I = $\frac{1}{3} mL^{2}$

τ = F d, d = $\frac{L}{2}$ cosθ

τ = m g $\frac{L}{2}$ cosθ

now we can substitute the both equation,

τ = Iα

α = τ/I

= (m g $\frac{L}{2}$ cosθ)/( $\frac{1}{3} mL^{2}$ )

= 3gcosθ/2L

= 3 (9.8)cos 38°/(2 x 1.2)

= 9.7 rad/ $s^{2}$

3 0

3 years ago

A long copper rod of diameter 2.0 cm is initially at a uniform temperature of 100°C. It is now exposed to an air stream at 20°C

Lisa [10]

Answer:

t = 4.0 min

Explanation:

given data:

diameter of rod = 2 cm

T_1 = 100 degree celcius

Air stream temperature = 20 degree celcius

heat transfer coefficient = 200 W/m2. K

WE KNOW THAT

copper thermal conductivity = k = 401 W/m °C

copper specific heat Cp = 385 J/kg.°C

density of copper = 8933 kg/m3

charateristic length is given as Lc

$Lc = \frac{V}{A_s}$

$Lc = \frac{\frac{\pi D^2}{4} L}{\pi DL}$

$Lc = \frac{D}{4}$

$Lc = \frac{0.02}{6} = 0.005 m$

Biot number is given as $Bi = \frac{hLc}{k}$

$Bi = \frac{200*0.005}{401}$

Bi = 0.0025

As Bi is greater than 0.1 therefore lumped system analysis is applicable

so we have

$\frac{T(t) - T_∞}{Ti - T_∞} = e^{-bt}$ ............1

where b is given as

$b = \frac{ hA}{\rho Cp V}$

$b = \frac{ h}{\rho Cp Lc}$

$b = \frac{200}{8933*385*0.005}$

b = 0.01163 s^{-1}

putting value in equation 1

$\frac{25-20}{100-20} = e^{-0.01163t}$

solving for t we get

t = 4.0 min

6 0

3 years ago

A train travels 120 km in 2 hours and 30 minutes. What is its average speed?

ivann1987 [24]

Answer:

13.33 or 13 1/3m/s (meters per second)

Explanation:

In physics, we use the basic units of meters and seconds. So first convert (km) into meters (m) and also hours and minutes into seconds (s). We end up with 120000m and 9000s. Then divide the 120000m by the 9000s and you end up with 13.33 or 13 1/3 m/s.

5 0

3 years ago

Read 2 more answers

jet is flying at 500 mph east relative to the ground. A Cessna is flying at 150 mph 60° north of west relative to the ground. Wh

Greeley [361]

Answer:

C. 590 mph

$\vert v_{cj}\vert=589.49\ mph$

Explanation:

Given:

velocity of jet, $v_j=500\ mph$
direction of velocity of jet, east relative to the ground
velocity of Cessna, $v_c=150\ mph$
direction of velocity of Cessna, 60° north of west

Taking the x-axis alignment towards east and hence we have the velocity vector of the jet as reference.

Refer the attached schematic.

So,

$\vec v_j=500\ \hat i\ mph$

&

$\vec v_c=150\times (\cos120\ \hat i+\sin120\ \hat j)$

$\vec v_c=-75\ \hat i+75\sqrt{3}\ \hat j\ mph$

Now the vector of relative velocity of Cessna with respect to jet:

$\vec v_{cj}=\vec v_j-\vec v_c$

$\vec v_{cj}=500\ \hat i-(-75\ \hat i+75\sqrt{3}\ \hat j )$

$\vec v_{cj}=575\ \hat i-75\sqrt{3}\ \hat j\ mph$

Now the magnitude of this velocity:

$\vert v_{cj}\vert=\sqrt{(575)^2+(75\sqrt{3} )^2}$

$\vert v_{cj}\vert=589.49\ mph$ is the relative velocity of Cessna with respect to the jet.

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3 years ago

Two trains are blowing their whistles. The first train is stationary, and the

Liono4ka [1.6K]

Answer:

A I think

Pls Mark Brainiest, I'm trying to become Virtuoso

3 0

3 years ago