I need to know the answer

When throwing a baseball overhand, what should you avoid?

daser333 [38]

when throwing a baseball overhand the muscles you use are

deltoids.

triceps.

latissimus dorsi.

abdominal muscles.

hips.

glutes.

so you should stretch and make sure you dont pull or hurt these muscles but you dont have to throw overhand Pitching underhand wasn't a gimmick for Gheen, it was his preferred style. He was mentioned in newspapers across the country for his unorthodox technique. An MLB umpire confirmed pitching underhand is allowed. also a good exercise to work out your arm would be A baseball push-up is meant to increase the power of your arms and core, and to increase the coordination between the two. This exercise also promotes good posture because it forces you to flex the muscles of the core in order to keep the lower back from bending.

and i'll leve you with a quick fact: Softball pitchers use an underhand motion that is not as stressful to the shoulder joint as the overhand pitch used in baseball. Softball pitchers can often pitch several games in one day, and often have an extended career of many years due to the lower stress levels on the shoulder joint.

good luck on your throwing!!

8 0

3 years ago

Do humans have a gravitational field if so, how strong

lilavasa [31]

I'm pretty sure that you have mass. When it comes to gravity, anything that has mass behaves exactly like anything else that has mass. Any two of them are attracted to each other, with a force that's proportional to the product of their masses, and inversely proportional to the square of the distance between them.

Now, if you have mass, then you have weight ... it's the answer you give when somebody asks "How much do you weigh ?". That's the force of gravity between you and the Earth, pulling you toward the center of the Earth. But it doesn't stop there. There's also a force of gravity pulling the Earth toward the center of you. The strength of it is EQUAL to your weight.

Your weight on Earth is EQUAL to the Earth's weight on YOU !

7 0

3 years ago

Read 2 more answers

Derive the following equations of motion

xz_007 [3.2K]

Answer:

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<h3>a. Let us assume a body has initial velocity 'u' and it is subjected to a uniform acceleration 'a' so that the final velocity 'v' after a time interval 't'. Now, By the definition of acceleration, we have:</h3>

$a = \frac{v - u}{t} \\ or \: at = v - u \\ v = u + at \:$

It is first equation of motion.

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<h3>b. Let us assume a body moving with an initial velocity 'u'. Let it's final body 'v' after a time interval 't' and the distance travelled by the body becomes 's' then we already have,</h3>

$v = u + at...........(i) \\ s = \frac{u + v}{2} \times t.........(ii)$

Putting the value of v from the equation (i) in equation (ii), we have,

$s= \frac{u + (u + at)}{2} \times t \: \: \\ or \: s = \frac{(2u + at)t}{2} \\ or \: s = \frac{2ut + a {t}^{2} }{2} \\ s = ut + \frac{1}{2} a {t}^{2}$

It is third equation of motion.

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<h3>c. Let us assume a body moving with an initial velocity 'u'. Let it's final velocity be 'v' after a time and the distance travelled by the body be 's'. We already have,</h3>

$v = u + at.....(i) \\ s = \frac{u + v}{2} \times t......(ii) \\$

$v = u + at \\ or \: at = v - u \\ t = \frac{v - u}{a}$

Putting the value of t from (i) in the equation (ii)

$s = \frac{u + v}{2} \times \frac{v - u}{a} \\ or \: s = \frac{ {v}^{2} - {u}^{2} }{2a} \\ or \: 2as = {v}^{2} - {u}^{2} \\ {v}^{2} = {u}^{2} + 2as$

It is forth equation of motion.

________________________________

Hope this helps...

Good luck on your assignment..

3 0

3 years ago

. Two astronauts are 1.90 m apart in their spaceship. One speaks to the other. The conversation is transmitted to earth via elec

melomori [17]

Answer:

d= 1650 km.

Explanation:

Assuming that sound waves travel along a straight line at a constant speed of 346 m/s, we can find the time needed for the sound to travel the distance of 1.9 m between the astronauts, just applying the definition of average velocity, as follows:

$t = \frac{\Delta x}{v} =\frac{1.9m}{346m/s} = 5.5 msec (1)$

The electromagnetic waves travel in free space at the same speed of light in vacuum ( since light is a electromagnetic wave indeed), i.e., 3*10⁸ m/s.
Applying the same formula than in (1) we can solve for the distance d, as follows:

$d = v*t = 3e8 m/s*5.5e-3s = 1650 km (2)$

3 0

3 years ago

Question 36 of 45

Setler [38]

Answer: vibrate

Explanation:

The object in air can be particular objects or substances.

Sound is actually vibration of waves through a medium. The medium can be liquid, solid or gas.

Therefore, the one word that will complete and make the sentence to make sense is ' vibrate '

7 0

4 years ago