We are tasked to solve for the volume of Gold given that the mass of Gold is equivalent to that of a copper.
Details:
Density of Copper= 8.96 g/ml
Volume of Copper=141 ml
mass of Gold = mass of Copper
Density of Gold=19.3 g/ml
In order to solve for the mass of copper, we need to use the density formula
Density= mass/volume
Since we are to solve for the mass of copper
mass of copper= Density of Copper * Volume of Copper
mass of copper= 8.96 g/ml* 141 ml= 1263.36 g
Thus,
mass of gold=mass of copper=1263.36 g
Hence,
Using still the density formula to solve for the volume of gold,
Volume of gold=mass of gold/ Density of gold
Volume of gold=1263.36 g/ 19.3 g/ml = 65.46 mL
Therefore, the volume of the gold must be 65.46 mL in order to have the same mass of a copper
Answer:
presence or absence of a nucleus
Explanation:
These classification of organisms into broad domains is based on the present or absence of nucleus in the cell of an organism.
The archaea are prokaryotes and they lack a distinct cellular nuclei.
Bacteria are similar to archaea but bacteria have only one RNA polymerase
Eukarya have true nucleus and membrane bound organelles .
So, the variations in their cells are used to classify organisms into the broad categories
Answer;
K+ and NO3- ions
Explanation;
The main ions remaining are K+ and NO3- ions after pbi2 precipitation is complete.
However; There will always be tiny amounts of Pb2+ and I- ions, but most of them are in the solid precipitate.
Use pv=nrT
where p is the pressure,
v is the volume,
n is the number of mole (which can be equal to mass /mr),
T is the temperature in kelvin,
and r is (molar constant) = 8.31 (units)
