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Ostrovityanka [42]
3 years ago
15

Which of the following explains how electrical charges flow? From areas of high-potential to areas of low-potential From areas o

f low-potential to areas of high-potential Electrical charges do not flow. From the detector to the source.
Physics
2 answers:
skad [1K]3 years ago
8 0
From areas of high potential to low potential.  That is, high voltage to low voltage.
Shalnov [3]3 years ago
8 0

Answer: From areas of high-potential to areas of low-potential.

Explanation:

Electrons are lighter particles and thus they flow. electric current is referred as the flow of electrons. Electrons flow from negative to positive terminal but electric current is conventionally considered to flow from high voltage to low i.e. high potential to low potential.

Thus, conventionally electric charges flow from high potential to low potential.

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Maurinko [17]

Resistivity of nichrome is high.

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3 years ago
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Once out in space, the space shuttle needs to _____ to keep going in the same direction at the same speed.
erik [133]

Answer:

C

Explanation:

because it not running will set it off course but running all the time it will run. out of fuel

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A negative charge -0.550 HC exerts an upward 0.700 N force on an unknown charge 0.220 m directly below it. (a) What is the unkno
Sonja [21]

Answer:

Part a)

q_2 = -6.8 \mu C

Part b)

F = 0.700 N

direction = downwards

Explanation:

As we know that the negative charge will experience the force due to some other charge below it

the force is given as

F = 0.700 N

now we know that

F = \frac{kq_1q_2}{r^2}

now plug in all data

0.700 = \frac{(9 \times 10^9)(0.550\mu C)q_2}{0.220^2}

0.700 = 1.022\times 10^5 q_2

q_2 = -6.8 \mu C

since this is a repulsion force so it must be a negative charge

Part b)

As per Newton's III law it will exert equal and opposite force on it

So here the force on the charge below it will be same in magnitude but opposite in direction

so here we have

F = 0.700 N

direction = downwards

4 0
3 years ago
What is newtons law of gravity
liq [111]

Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

7 0
4 years ago
A spaceprobe in outer space is flying with a constant speed of 1.530 km/s. The probe has a payload of 1363.0 kg and it carries 3
abruzzese [7]

Answer:

6.33 km/s

Explanation:

Given that :

A spaceprobe in outer space is flying with a constant speed v_i =  1.530 km/s.

The probe has a payload =  1363.0 kg

which carries 3486.0 kg of rocket fuel.

Exhaust speed = 3.795 km/s

How fast will the spaceprobe travel when all the rocket fuel is used up?

As we know that the rate of change of spaceprobe momentum is equal to the thrust of the rocket.

Then;

m \frac{dv}{dt} = -v_{ex} \frac{dm}{dt}

where;

v_{et  = exhaust speed

dv = -v_{ex}\frac{dm}{m}

Taking the integral of the above expression; we have:

v_f -v_i = - v_{ex}In m|^{m_f}_{m_o}

v_f -v_i = - v_{ex}In \frac{m_o}{m_f}

v_f  = v_i +  v_{ex}In \frac{m_o}{m_f}

v_f  =1.530 +  3.795 In (\frac{1363+3486}{1363} )

= 6.33 km/s

3 0
3 years ago
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