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MA_775_DIABLO [31]
3 years ago
7

Which kind of wave interaction is shown?

Physics
1 answer:
nlexa [21]3 years ago
3 0

Answer:

where?

Explanation:

ill edit my answer when see it

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What is the relationship between amplitude and frequency of a wave?.
kondaur [170]

Answer:

The relationship between the wave's amplitude and frequency is such that it is inversely proportional to the frequency. The amplitude decreases as the frequency increases. The amplitude increases as the frequency decreases. The higher the energy of a wave, the higher the amplitude. The lower the energy, the lower the amplitude. Energy has no effect on wavelength, speed, or frequency, only the amplitude.

Explanation:

5 0
2 years ago
What happens if you move a bar magnet back and forth along the axis of the
nadezda [96]

C) A current is induced in the coiled wire, which lights the light bulb

The moving magnetic field creates electricity which lights the light bulb

Hope it helps!

8 0
1 year ago
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At room temperature, sound travels at a speed of about 344 m/s in air. You see a distant flash of lightning and hear the thunder
beks73 [17]

Answer:

d=1.67mi

Explanation:

Assuming the light takes essentially no time to reach you, the distance at which the lightning occurred can be calculated by multiplying the speed of sound by the time it takes to hear the thunder:

d=v_st\\d=344\frac{m}{s}(7.8s)\\d=2683.2m*\frac{1mi}{1609.34m}=1.67mi

4 0
3 years ago
Which of the following is the best example of a good hypothesis?
Musya8 [376]

Answer:

Which of the following is the best example of a good hypothesis?

B. A cheetah can run faster than a tiger This Is A good Hypothesis Because You Can Test this With a Experiment

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4 0
3 years ago
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g A bowling ball with a mass of 3.86 kg and a radius of 0.161 m starts from rest at a height of 2.5 m and rolls down a 48.4 o sl
Fynjy0 [20]

Answer:

v=1.5m/s

Explanation:

The gravitational potential energy gets transformed into translational and rotational kinetic energy, so we can write mgh=\frac{mv^2}{2}+\frac{I\omega^2}{2}. Since v=r\omega (the ball rolls without slipping) and for a solid sphere I=\frac{2mr^2}{5}, we have:

mgh=\frac{mv^2}{2}+\frac{2mr^2\omega^2}{2*5}=\frac{mv^2}{2}+\frac{mv^2}{5}=\frac{7mv^2}{10}

So our translational speed will be:

v=\sqrt{\frac{10gh}{7}}=\sqrt{\frac{10(9.8m/s^2)(0.161m)}{7}}=1.5m/s

6 0
3 years ago
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