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SOVA2 [1]
3 years ago
15

A ball is thrown horizontally from the top of a building and strikes the sidewalk after 2.8 s. How tall is the building? Neglect

air resistance.
Physics
1 answer:
Brut [27]3 years ago
3 0

Answer:

h = 38.41 m

Explanation:

Given that,

A ball is thrown horizontally from the top of a building and strikes the sidewalk after 2.8 s.

We need to find the height of the building. Let it is h.

Initial speed of the ball, u = 0

Using second equation of motion to find h as follows :

h=ut+\dfrac{1}{2}at^2\\\\\text{Put u = 0 and a = g}\\\\h=\dfrac{1}{2}gt^2\\\\=\dfrac{1}{2}\times 9.8\times 2.8^2\\\\=38.41\ m

So, the building is 38.41 m tall.

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Inessa05 [86]

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<em>v</em> = <em>v</em>₀ + <em>a</em> <em>t</em>

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<em />

If we force is halved, so is the accleration:

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3 years ago
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777dan777 [17]

Answer:

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