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zubka84 [21]
3 years ago
6

An object moving in a straight line is decelerating. Which about its acceleration is necessarily true?

Physics
1 answer:
Varvara68 [4.7K]3 years ago
3 0

Answer:

Its acceleration is certainly negative.

Explanation:

  • When an object moving in a straight line decelerates then its velocity certainly decreases.
  • Its acceleration is certainly negative.
  • As we know that acceleration is the rate of change in velocity and the object is decelerating i.e. its velocity is reducing with time.

a=\frac{v_f-v_i}{t_f-t_i}

where:

v_f\ \&\ v_i are final and initial velocities of the object

t_f\ \&\ t_i are final and initial time of observation.

  • Its SI unit is m.s^{{-2}
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Answer:

A

Explanation:

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3 years ago
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A student constructed a series circuit consisting of a 12.0-volt battery, a 10.0-ohm lamp, and a
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     Considering the unknown resistence as R and using the Ohm's First Law, we have:

i= \frac{V}{R_{eq}}  \\ 0.5= \frac{12}{R+10}  \\ R+10=24 \\ R=14-Ohm
 
     The equivalent resistence is given by the resistor series with the lamp resistence.

R_{eq}=R+10 \\ R_{eq}=14+10 \\ \boxed {R_{eq}=24-Ohm}

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6 0
3 years ago
You wish to cool a 1.83 kg block of tin initially at 88.0°C to a temperature of 57.0°C by placing it in a container of kerosene
uranmaximum [27]

Answer:

0.273 liters are needed to accomplish this task without boiling.

Explanation:

The minimum boiling point of kerosene is 150\,^{\circ}C. According to this question, we need to determine the minimum volume of liquid such that heat received is entirely sensible, that is, with no phase change.

If we consider a steady state process and that energy interactions with surrounding are negligible, then we get the following formula by the Principle of Energy Conservation:

\rho_{k}\cdot V_{k}\cdot c_{k}\cdot (T-T_{k,o}) = m_{t}\cdot c_{t}\cdot (T_{t,o}-T) (1)

Where:

\rho_{k} - Density of kerosene, measured in kilograms per cubic meter.

V_{k} - Volume of kerosene, measured in cubic meters.

c_{k}, c_{t} - Specific heats of the kerosene and tin, measured in joule per kilogram-Celsius.

T_{k,o}, T_{t,o} - Initial temperatures of kerosene and tin, measured in degrees Celsius.

T - Final temperatures of the kerosene-tin system, measured in degrees Celsius.

Please notice that the block of tin is cooled at the expense of the temperature of the kerosene until thermal equilibrium is reached.

From (1), we clear the volume of kerosene:

V_{k} = \frac{m_{t}\cdot c_{t}\cdot (T_{t,o}-T)}{\rho_{k}\cdot c_{k}\cdot (T-T_{k,o})}

If we know that m_{t} = 1.83\,kg, c_{t} = 218\,\frac{J}{kg\cdot ^{\circ}C}, T_{t,o} = 88\,^{\circ}C, T_{k,o} = 24.0\,^{\circ}C, T = 57\,^{\circ}C, c_{k} = 2010\,\frac{J}{kg\cdot ^{\circ}C} and \rho_{k} = 820\,\frac{kg}{m^{3}}, then the volume of the liquid needed to accomplish this task without boiling is:

V_{k} = \frac{(1.83\,kg)\cdot \left(218\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (88\,^{\circ}C-57\,^{\circ}C)}{\left(820\,\frac{kg}{m^{3}} \right)\cdot \left(2010\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (57\,^{\circ}C-24\,^{\circ}C)}

V_{k} = 2.273\times 10^{-4}\,m^{3}

V_{k} = 0.273\,L

0.273 liters are needed to accomplish this task without boiling.

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3 years ago
Which school of thought did sigmund freud’s the interpretation of dreams support?
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Which describes an atom that has fewer neutrons than protons and more electrons than protons?
aleksklad [387]

Answer:

negative ion

Explanation:

An atom that has fewer neutrons than protons and more electrons than protons is a negative ion.

The positively charged particles in an atom are the protons

The negatively charged particles in an atom are the electrons.

  The charge an atom carries depends on the balance between the number of protons and electrons in an atom.

  • When the number of protons is more than the number of electrons, the atom is positively charged.
  • When the number of electrons is more than the number of protons, the atom is negatively charged.
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