3 years ago

An object moving in a straight line is decelerating. Which about its acceleration is necessarily true?

Physics

1 answer:

Varvara68 [4.7K]3 years ago

3 0

Answer:

Its acceleration is certainly negative.

Explanation:

When an object moving in a straight line decelerates then its velocity certainly decreases.

Its acceleration is certainly negative.

As we know that acceleration is the rate of change in velocity and the object is decelerating i.e. its velocity is reducing with time.

$a=\frac{v_f-v_i}{t_f-t_i}$

where:

$v_f\ \&\ v_i$ are final and initial velocities of the object

$t_f\ \&\ t_i$ are final and initial time of observation.

Its SI unit is $m.s^{{-2}$

You might be interested in

(PLEASE HELP THANK YOU) A car is going 8 meters per second on an access road into a highway and then accelerates at 1.8 meters p

jonny [76]

Answer:

20.96 m/s

Explanation:

Apply the kinematic equation:

Vf=Vi+at

Vi=8m/s

a=1.8m/s^2

t=7.2s

Putting this all in should give you your answer of 12.96m/s

6 0

3 years ago

Two forces act at a point in the plane. The angle between the two forces is given. Find the magnitude of the resultant force. fo

Zielflug [23.3K]

Answer:

408N at 89.89°

Explanation:

This problem requires that we resolve the force vectors into

x- and y

-componentsOnce this is done, we can add the components easily, as the one 2-dimensional problem will be two 1-dimensional problems.

Finally, we will convert the resultant force into standard form and find the equilibrant.

Resolve into components:

F1x =F1cos 180°= 232(−1)=−232N

F1y=F1sin180°=0N

F2x=F2cos(−140°)=194(−0.766)=−148.6N

F1y=F1sin(−140°)=232(−0.643)=−149.17N

Note the change of the angle used to give the direction of

F2. Standard angles (rotation from thex

-axis; counterclockwise is +) should be used to avoid sign errors in the results.

Now, we add the components:

Fx=F1x+F2x=−380.6N

Fy=F1y+F1y=−148.17N

Technically, this is the resultant force. However, it should be changed back into standard form. Here's how:

F=√(Fx)2(Fy)2=√(−380.6)^2(−148.17)^2=408N

θ=tan−1(−148.17−380.6)

=89.89°

4 0

3 years ago

Your friends sit in a sled in the snow. If you apply a force of 95 N to them, they have an acceleration of 0.8 m/s2. What is the

ss7ja [257]

F=ma
m=F/a=95/0.8= 118.75kg
your friend is pretty heavy XD

5 0

2 years ago

Read 2 more answers

Which technological advance allows scientists to handle these objects enough to feel their properties while still protecting the

muminat

The answer depends heavily on what 'objects' you're talking about.

5 0

3 years ago

Read 2 more answers

When you enter a toll road, your ticket is stamped 1:00 p.m. When you leave, after traveling 55 miles, your ticket is stamped 2:

Viefleur [7K]

27.5 because of you divide the 55miles with the time you get your velocity which is the speed.

4 0

2 years ago

Read 2 more answers