The resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.
The given parameters:
- Mass of the box, m = 31 kg
- Two applied forces, = 8.3 N and 6.6 N
<h3>Resultant force on the box</h3>
The resultant force on the box is calculated as follows;
<h3>Resultant acceleration of the box</h3>
The resultant acceleration of the box is calculated as follows;
Thus, the resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.
Learn more about resultant acceleration here: brainly.com/question/26216029
Answer:
1.) A simple harmonic oscillator has an amplitude of 3.50 cm and a maximum speed of 26.0 cm/s. What is its speed when the displacement is 1.75 cm? 2.) Both pendulum A and B are 3.0 m long. The period of A is T. Pendulum A is twice as heavy as pendulum B. What is the period of B? 3.) The time for one cycle of a periodic process is called the _ ? 4.) In simple harmonic motion, the acceleration is proportional to? 5.) The position of a mass that is oscillating on a spring is given by x= (18.3 cm) cos [(2.35 s-1)t]. What is the frequency of this motion?
Explanation:
Answer:
it loaded and it is C. buddy sorry about that :)
The frequency of a wave is the number of waves that passes through a point in a certain time. The less waves that pass in a period of time the lower the frequency of the wave. The more waves that pass in a period of time the higher the frequency of the wave. When measuring wave length the time period used is usually one second.
