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Vesna [10]
2 years ago
10

What is the force exerted on a moving charge of –2.0 μC at a 20° angle through a magnetic field of 3.0 × 10–4 T with a velocity

of 5.0 × 106 m/s?
3.0 × 10–3 N
1.0 × 10–3 N
1.0 × 103 N
Physics
2 answers:
san4es73 [151]2 years ago
6 0
1.0 x 10-3 N is the correct answer!
a_sh-v [17]2 years ago
5 0
The answer is B 1.0 * 10 -3 N
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Find the kenetic energy of a car of mass 700kg racing with a velocity of 10m/s
fiasKO [112]

Answer:

35000 KJ

Explanation:

The equation for the kinetic energy is given by the formula :

E_{k} = \frac{1}{2} mv^{2}

E_{k} = \frac{1}{2} (700)(10)^{2}

E_{k} = \frac{1}{2} (700)(100)

E_{k} = (350)(100)  OR E_{k} = \frac{1}{2} (70000)

E_{k} = 35000

Units will be kilojoules since the units of mass was kilograms .

Our final answer is 35000 KJ

Hope this helped and have a good day

5 0
2 years ago
The nutritional calorie (Calorie) is equivalent to 1 kilocalorie. One pound of body fat is equivalent to about 4.10 × 103 Calori
FrozenT [24]

Answer:

Explanation:

Using

4.01 × 10^3 * 4.186 = 1.72×10^4j

In KJ 17.2kj

6 0
3 years ago
Specific heat is the amount of heat required to raise the temperature of a material by 1°C per what unit?
nydimaria [60]

The heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).


or C. Mass if you're on plato

3 0
2 years ago
Read 2 more answers
What can you predict about an element from its position in the periodic table
bazaltina [42]
Based on its position in the periodic table, you can predict how many electrons it has, how many valence electrons, how many levels of electrons, and its atomic number and mass.
5 0
3 years ago
Near the surface of Earth an electric field points radially downward and has a magnitude of approximately 100 N/C. What charge (
pentagon [3]

Answer:

q=2.997\times 10^{-4}C

Sign-Negative

Explanation:

We are given that

Electric field =E=100NC^{-1} (Radially downward)

Acceleration=0.19 ms^{-2}(Upward)

Mass of charge=3 g=3\times 10^{-3}kg

1kg=1000g

We have to find the magnitude and sign of  charge would have to be placed on a penny .

By newton's second law

\sum F_y=ma

\sum F_y=qE-mg

Substitute the values then we get

qE-mg=ma

Substitute the values then we get

q(100)-3\times 10^{-3}(9.8)=3\times 10^{-3}(0.19)

100q-29.4\times 10^{-3}=0.57\times 10^{-3}

100q=0.57\times 10^{-3}+29.4\times 10^{-3}=29.97\times 10^{-3}

q=\frac{29.97\times 10^{-3}}{100}

q=2.997\times 10^{-4}C

Sign of charge =Negative

Because electric force acting  in opposite direction of electric field therefore,charge on penny will be negative.

4 0
3 years ago
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