Ask question

Ask question

All categories

3 years ago

10

What is the force exerted on a moving charge of –2.0 μC at a 20° angle through a magnetic field of 3.0 × 10–4 T with a velocity

of 5.0 × 106 m/s?
3.0 × 10–3 N
1.0 × 10–3 N
1.0 × 103 N

2 answers:

san4es73 [151]3 years ago

6 0

1.0 x 10-3 N is the correct answer!

a_sh-v [17]3 years ago

5 0

The answer is B 1.0 * 10 -3 N

You might be interested in

you have been provided with an insulated wire , voltmeter or a battery with a charge of 10ohms, a bulb, a switch and a resistor

eduard

I’m trying to get my points up I have the same question

4 0

3 years ago

32. A ball is going to fall downward through a vacuum chamber. If it has maximum potential energy at the top and maximum kinetic

QveST [7]

Half maximum velocity occurs at the point of half maximum kinetic energy which is exactly halfway down.

<h3>Conservation of energy</h3>

The principle of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

M.A = K.E + P.E

At the maximum height, the kinetic energy of the ball while potential energy is maximum.

At the half-way down, the ball kinetic energy of the ball is equal to the potential energy.

Thus, half maximum velocity occurs at the point of half maximum kinetic energy which is exactly halfway down.

Learn more about kinetic energy here: brainly.com/question/25959744

8 0

1 year ago

1.a machine gun fires a ball with an initial velocity of 600m/s with an elevation of 30° with respect to the ground neglecting a

Sedbober [7]

Answer:

See explanation

Explanation:

a) maximum height of a projectile = u sin^2θ/2g

H= 600 × (sin 30)^2/2 × 10

H= 7.5 m

b) Time of flight

t= 2u sinθ/g

t= 2 × 600 sin 30/10

t= 60 seconds

Range

R= u^2sin2θ/g

R= (600)^2 × sin2(30)/10

R= 31.2 m

3 0

2 years ago

Help ASAP, will give you brainliest!

Stels [109]

Answer:

A

Explanation:

5 0

3 years ago

Read 2 more answers

How do your results from ray tracing compare to your results from using the thin-lens equation?

EastWind [94]

Answer:

20cm

Explanation:

A convex lens has a positive focal length and the object placed in front of it produce both virtual and real image <em>(image distance can be negative or positive depending on the nature of the image</em>).

According to the lens equation

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$ where;

f is the focal length of the lens

u is the object distance

v is the image distance

If the magnification is - 0.6

mag = v/u = -0.5

v = -0.5u

since v = 10cm

10 = -0.5u

u = -10/0.5

u =-20 cm

Substitute u = -20cm ( due to negative magnification)and v = 10cm into the lens formula to get the focal length f

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{-1+2}{20} \\\frac{1}{f} = \frac{1}{20} \\cross \ multiply\\f = 20\\f = 20 cm$

Hence the focal length of the convex lens is 20cm

7 0

3 years ago