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2 years ago

A net force of 345 N accelerates a boy on a sled at 3.2 m/s^2 . What is combined mass of the sled

Physics

1 answer:

Daniel [21]2 years ago

6 0

Answer:

Mass, m = 26.54kg

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

$Fnet = Fapp + Fg$

Where;

Fnet is the net force

Fapp is the applied force

Fg is the force due to gravitation

<u>Given the following data;</u>

Net force, Fnet = 345

Acceleration, a = 3.2m/s²

Fnet = Fapp + Fg

Fnet = ma + mg

Fnet = m(a+g)

m = Fnet/(a+g)

We know that acceleration due to gravity, g = 9.8m/s²

Substituting into the equation, we have;

m = 345/(3.2 + 9.8)

m = 345/13

Mass, m = 26.54kg

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garik1379 [7]

Explanation:

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2 years ago

Read 2 more answers

4) A motorcycle travels at a constant 90 km per hour in the positive direction down a straight line highway.

ipn [44]

Answer:

1875 meters

Explanation:

We are given;

Velocity of the motorcycle as 90 km/hr
Time as 75 seconds

We are required to calculate the displacement;

First we will convert speed to m/s
The suitable conversion factor will be;

1 m/s = 3.6 km/hr

Therefore, 90 km/hr

= 90 km/hr ÷ 3.6 km/hr per m/s

= 25 m/s

But;

Displacement = Velocity × time

Thus;

Displacement = 25 m/s × 75 seconds

= 1875 meters

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2 years ago

What is the same about each type of electromagnetic wave?

ehidna [41]

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2 years ago

Astronauts on the first trip to Mars take along a pendulum that has a period on earth of 1.26 s. The period on the other planet

Angelina_Jolie [31]

Answer:

1.066 m/s^2

Explanation:

On the earth and on Mars respectively, the time periods of the pendulums are expressed as:

Tearth = 2pi * sqrt(L/gearth)

Tmars = 2pi * sqrt(L/gMars)

Divide the two equations above:

Tearth/Tmars = sqrt(gMars/gearth)

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2 years ago

Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound?

Hitman42 [59]

The height, h to which the package of mass m bounces to depends on its initial velocity, v and the acceleration due to gravity, g and is given below:

$h = \frac{v^{2}}{2g}$

<h3>What are perfectly elastic collision?</h3>

Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.

In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.

Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.

Since some of the Kinetic energy is converted to potential energy of the body;

$\frac{mv^{2}}{2} = mgh$

$h = \frac{v^{2}}{2g}$

Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.

Learn more about elastic collisions at: brainly.com/question/7694106

7 0

1 year ago