1.3 second of time will be required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 105 km
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What is Speed ?</h3>
Speed is the distance travelled per time taken. It is a scalar quantity. And the S.I unit is meter per second. That is, m/s
In the given question, we want to find how much time is required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 10^5 km.
What are the parameters to consider ?
The parameters are;
- The distance S = 3.85 ×
km
- The Speed of Light C = 3 ×
m/s
Speed = distance S ÷ Time t
Convert kilometer to meter by multiplying it by 1000
C = S/t
3 ×
= 3.85 ×
/ t
Make t the subject of formula
t = 3.85 ×
/ 3 × 
t = 1.2833
t = 1.3 s
Therefore, 1.3 second of time will be required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 105 km
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Forces of gravity and magnets.
You said 2 revolutions every 0.08 seconds
1 revolution = 2pi radians.
A). The 'unit rate' is (2 rev) x (2pi / 0.08 sec) = 50pi radians/sec. =
157.1 radians per sec (rounded)
B). Radius of the wheel = 30 cm
Circumference = 2pi R = 60pi cm = 188.5 cm (rounded)
Rotation speed = 2 revs per 0.08 sec
Linear speed = 2 x 60pi cm per 0.08 sec
(120pi cm) / (0.08 sec) = 47.12 meters per sec
C). Frequency = (revs) per second
= (2) / (0.08 sec) = 25 per second .
Answer:
k_2 =3826.08 J
K_1 = 4973.91 J
Explanation:
from conservation of momentum principle

we know that kinetic energy is given as


we have
, 
therefore 
now


k_2 =3826.08 J
K_1 = 4973.91 J
Answer:
The energy would remain equal to that of the initial kinetic energy since it is a frictionless surface. However if it is an inelastic collision then energy would be lost due to sound and heat.
Explanation: