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Darina [25.2K]
3 years ago
11

Why the efficiency of normal light is smaller than solar light ??

Physics
1 answer:
stellarik [79]3 years ago
8 0

Answer:

part of energy is wasted in heat because of resistance in the filament (and that's how it glows)

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The bowl now contains . Milliters of oil
Sergeeva-Olga [200]
Data????????????????????????????
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3 years ago
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Select the situation for which the torque is the smallest.
alina1380 [7]

Answer:

e. The torque is the same for all cases.

Explanation:

The formula for torque is:

τ = Fr

where,

τ = Torque

F = Force = Weight (in this case) = mg

r = perpendicular distance between force an axis of rotation

Therefore,

τ = mgr

a)

Here,

m = 200 kg

r = 2.5 m

Therefore,

τ = (200 kg)(9.8 m/s²)(2.5 m)

<u>τ = 4900 N.m</u>

<u></u>

b)

Here,

m = 20 kg

r = 25 m

Therefore,

τ = (20 kg)(9.8 m/s²)(25 m)

<u>τ = 4900 N.m</u>

<u></u>

c)

Here,

m = 8 kg

r = 62.5 m

Therefore,

τ = (8 kg)(9.8 m/s²)(62.5 m)

<u>τ = 4900 N.m</u>

<u></u>

Hence, the correct answer will be:

<u>e. The torque is the same for all cases.</u>

6 0
4 years ago
I can't seem to get the right angular acceleration and also not sure how to do part b. Help will be much appreciated.
Tcecarenko [31]

Answer:It’s 5 I believe

Explanation: it says to round to the nearest thousandths, so it’ll be 5.

8 0
3 years ago
HELPPPPPPPP!!!!! PLZZZ
Gennadij [26K]

Answer:

1- 31.25

2-?

3-?

Explanation:

6 0
3 years ago
Read 2 more answers
A spacecraft in the shape of a long cylinder has a length of 100 m, and its mass with occupants is 1 480 kg. It has strayed too
maks197457 [2]

Answer:

2352645198509.9604 m/s²

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of black hole = 90\times 1.989\times 10^{30}\ kg

R_{f} = 10000+100 m

R_{sb} = Distance between the nose and the center of the black hole = 10000 m

The difference in the gravitational field in this system is given by

\Delta F=\dfrac{GMm}{R_{f}^2}-\dfrac{GMm}{R_{sb}^2}\\\Rightarrow \Delta g=GM\left(\frac{1}{R_f^2}-\frac{1}{R_{sb}^2}\right)\\\Rightarrow g=6.67\times 10^{-11}\times 90\times 1.989\times 10^{30}\left(\frac{1}{(10000+100)^2}-\frac{1}{10000^2}\right)\\\Rightarrow \Delta g=-2352645198509.9604\ m/s^2

The acceleration is 2352645198509.9604 m/s²

4 0
3 years ago
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