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polet [3.4K]
3 years ago
14

Which is found farthest from the center of an atom?

Physics
1 answer:
xxTIMURxx [149]3 years ago
5 0
Electron

Hope this helps
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Two or more explanatory variables that are not separated best describes which of the choices below?
OverLord2011 [107]
"Confounding variable" is the choice among the following choices given in the question that best describes two <span>or more explanatory variables that are not separated. The correct option among all the options that are given in the question is the second option or option "b". I hope the answer has come to your help.</span>
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3 years ago
The light bulb in your room is not very bright. You want to use a concave mirror to direct its illumination into a tight, parall
ehidna [41]

A point source is to be used with a concave mirror to produce a beam of parallel light. The source should be placed midway between the center of curvature and the mirror. To solve this question you have to draw a ray diagram. Apply the mirror equation to determine the image distance and finally make sure that the first two steps are consistent with each other.


<span>I hope this helps, Regards.</span>

5 0
3 years ago
For a spacecraft or a molecule to leave the moon, it must reach the escape velocity (speed) of the moon, which is 2.37 km/s. The
guapka [62]

Answer:

Vrms = 291 m/s

Explanation:

The root mean square velocity or vrms is the square root of the average square velocity and is. vrms=√3RTM. Where M is equal to the molar mass of the molecule in kg/mol.

Temperature = 365 K

Root mean square velocity = ?

molar mass of oxygen = 16 g/mol.

But xygen gas (O2) is comprised of two oxygen atoms bonded together. Therefore:

   molar mass of O2 = 2 x 16

   molar mass of O2 = 32 g/mol

   Convert this to kg/mol:

   molar mass of O2 = 32 g/mol x 1 kg/1000 g

   molar mass of O2 = 3.2 x 10-2 kg/mol

Molar mass of Oxygen = 3.2 x 10-2 kg/mol

Vrms = √[3(8.3145 (kg·m2/sec2)/K·mol)(365 K)/3.2 x 10-2 kg/mol]

Vrms = 291 m/s

8 0
3 years ago
Read 2 more answers
A high power line carries a current of 1.0 kA. What is the strength of the magnetic field this line produces at the ground, 10 m
solmaris [256]

Answer:

The strength of the magnetic field that the line produces is 2x10^{-5} Tesla.

Explanation:

From Biot-Savart law, the equation to determine the strength of the magnetic field for any straight wire can be deduced:

           

B = \frac{\mu_{0}I}{2\pi r} (1)      

                                     

Where \mu_{0} is the permiability constant, I is the current and r is the distance from the wire.    

             

Notice that it is necessary to express the current, I, from kiloampere to ampere.

I = 1.0kA \cdot \frac{1000A}{1kA} ⇒ 1000A

Finally, equation 1 can be used:

B = \frac{(4\pi x10^{-7}T.m/A)(1000A)}{2\pi (10m)}    

           

B = 2x10^{-5}T    

Hence, the strength of the magnetic field that the line produces is 2x10^{-5} Tesla.

         

8 0
3 years ago
Complete the equation???
soldi70 [24.7K]

Here in nuclear reaction we can say that sum of neutrons and protons in reactant side and product side will be same always

Here mass number on the product side is given to us

so sum of mass number is given as

A_1 + A_2 = 265 + 1 = 266

now on the reactant side also the number must be same

A_1' + A_2' = 58 + x

now we will have

58 + x = 266

x = 208

Now number of protons on product side is given as

P_1 + P_2 = 108 + 0

now we also know that atomic number of Fe is 26

so now we will have

P_1' + P_2' = 108

26 + P_2' = 108

P_2' = 82

now the equation is given as

_{26}^{58}Fe + _{82}^{208}Pb = _{108}^{266}Hs + _0^1X

8 0
3 years ago
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