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IRISSAK [1]
3 years ago
7

Air at 7 deg Celcius enters a turbojet engine at a rate of 16 kg/s and at a velocity of 300 m/s (relative to engine). Air is hea

ted in the combustion chamber and it leaves the engine at 427 deg Celcius. Determine the thrust produced by this turbojet engine.
Engineering
1 answer:
Savatey [412]3 years ago
4 0

To solve this problem we will start using the given temperature values and then transform them to the Kelvin scale. From there through the properties of the tables, described for the Air, we will find the entropy. With these three data we can perform energy balance and find the speed of the fluid at the exit, which will finally help us find the total force:

V_i = 300m/s

T_1 = 7\°C = 280K

T_2 = 427\°C = 700K

\dot{m} 16kg/s

\dot{Q}_{in} = 15000kJ/s

Using the tables for gas properties of air we can find the enthalpy in this two states, then

T_1 = 280K \rightarrow h_1 = 280.13kJ/Kg\cdot K

T_2 = 700K \rightarrow h_2 = 713.27kJ/Kg\cdot K

Applying energy equation to the entire engine we have that

\frac{\dot{Q}_{in}}{\dot{m}}+h_1 +\frac{1}{2} V^2_{in} = h_2 + \frac{1}{2} V^2_{out}

\frac{15000}{16}*10^3+280.13*10^3+\frac{1}{2} 300^2 = 713.27*10^3+\frac{1}{2} V^2_{out}

V_{out} = 1048.198m/s

Finally the force in terms of mass flow and velocity is

F = \dot{m} (V_{out}-V_{in})

F = 16(1048.198-300)

F= 11971.168N

Therefore the thrust produced by this turbojet engine is  11971.168N

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Explanation: Electric current is measured in amperes, usually shortened to amps.

6 0
3 years ago
The USAF is thinking of purchasing a improved automatic controller (no human required) at a cost of $100,000 that can make 4,000
blsea [12.9K]

Answer:

It would take 3225.8 hours of target detection to pay off the new controller

Explanation:

First, to find out how many hours it would take, we calculate what is the cost per contact for both options:

\mbox{cost per contact}=\frac{\mbox{cost per hour}}{\mbox{contacts per hour}} \\\\\mbox{cost per contact}_{specialist} =\frac{8 \frac{\$}{h} }{1000\frac{contacts}{hour} } =8*10^{-3} \frac{\$}{contact}\\\\\mbox{cost per contact}_{controller} =\frac{1 \frac{\$}{h} }{4000\frac{contacts}{hour} } =2.5*10^{-4} \frac{\$}{contact}

Knowing the cost per contact, we calculate savings per contact when using the controller:

Savings=\mbox{cost per contact}_{specialist}-\mbox{cost per contact}_{controller}\\Savings=8*10^{-3} \frac{\$}{contact}-2.5*10^{-4} \frac{\$}{contact}=7.75*10^{-3} \frac{\$}{contact}

Now that we know how much the automatic controller saves, we calculate how many contacts it would take to pay it off, and then, taking into account contacts per hour, how many hours:

Hours=\frac{\mbox{cost of the controller}}{\mbox{savings per contact}}*\frac{\mbox{1}}{\mbox{contacts per hour}}  \\\\Hours=\frac{\$100000}{7.75*10^{-3} \frac{\$}{contact}} *\frac{\mbox{1}}{4000\frac{contacts}{hour} }}=3225,8 \mbox{ hours}

That means, without taking into account veteran benefits (that raise the cost of the USAF specialist), it would take around 134 days of target detection to pay off the new controller.

8 0
3 years ago
The minimum size for overhead service conductors shall not be smaller than ____ AWG copper. A. 4 B. 6 C. 8 D. 10
ivolga24 [154]

Answer: C. 8AWG

Explanation: According to the NEC system

4 0
3 years ago
A mass of 7 kg undergoes a process during which there is heat transler frorn the mass at a rate of 2 kJ per kg, an elevation dec
irinina [24]

Answer:44.61 KJ

Explanation:

Let h_1,V_1,Z_1 be the initial specific enthalpy,velocity&elevation of the system

and h_2,V_2,Z_2 be the Final specific enthalpy,velocity&elevation of the system

mass(m)=7kg

Applying Steady Flow Energy Equation

m\left [ h_1+\frac{v_1^2}{2g}+gZ_1\right ]+Q=\left [ h_2+\frac{v_2^2}{2g}+gZ_2\right ]+W

h_1-h_2=4 KJ/kg

V_1=13m/s

V_2=23m/s

Z_1-Z_2=40m

substituting values

7\left [ h_1+\frac{13^{2}}{2g}+gZ_1\right ]+7\times2 = \left [ h_2+\frac{23^2}{2g}+gZ_2\right ]+W

W=7\left [h_1-h_2+\frac{V_1^2-V_2^2}{2000g}+g\frac{\left (Z_1-Z_2 \right )}{1000}\right ]+Q

W=7\left [4+\frac{13^2-23^2}{2000g}+g\frac{\left (40 \right )}{1000}[\right ]+2\times 7

W=44.61KJ

4 0
3 years ago
Which is not a requirement for raising crops?​
USPshnik [31]

Explanation:

Since there are no answer choices, how do we answer this? comment the answer choices below and ill edit this

8 0
3 years ago
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