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Reil [10]
3 years ago
10

"12 cents per kilowatt-hour (kwh), a 114 MPGe (combined) Nissan Leaf costs 90 cents per 25 miles,"

Engineering
1 answer:
snow_lady [41]3 years ago
4 0

Explanation:

25 mi × (1 gallon-equivalent / 114 mi) = 0.219 gallon-equivalent

0.219 gallon-equivalent × (34 kWh / gallon-equivalent) = 7.46 kWh

7.46 kWh × (12 cents / kWh) = 89.5 cents

Rounded up to the nearest cent, it costs 90 cents per 25 miles.

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What is the connection between the air fuel ratio and an engine running rich/poor? please give clear examples and full sentances
gavmur [86]

Explanation:

Air fuel ratio:

 Air fuel ratio is the ratio of mass of air to the mass of fuel.So we can say that

Air\ fuel\ ratio=\dfrac{mass\ of\ air}{mass\ of\ fuel}

As we know that fuel burn in the presence of air that is why we have to maintain a proper amount of air fuel ratio.

When we need more power then we have supply more fuel and to burn this fuel ,require a specified amount of air.So for different loading condition of engine different air fuel ratio is required.

When air is less and fuel is more then it is called rich air fuel ratio .when air is more and fuel is less then it is called poor air fuel ratio.

5 0
4 years ago
Which of the following tape measure techniques can be used to achieve accurate measurements? Choose all that apply.
zepelin [54]

Answer: Pull.

Because it's all about height width and Breadth!

5 0
3 years ago
Who ate cdonalds in hell with god then died from food ppoisoning
siniylev [52]

Answer:

McDonald’s announced recently that they are going through some major menu changes, and will be nixing some unnecessary ingredients. They also are finally listening to us, and will stop using chickens that are injected with growth-promoting antibiotics, along with dairy products raised with the growth hormone rbST but they still are using a lot of factory farmed meat and the beef is still raised with antibiotics.

McDonald’s even said they might add kale to their menu, by putting it in salads or in a smoothie. I LOVE kale, and I hope they don’t find a way to ruin it. You know the saying, “You can put lipstick on a pig, but it’s still a pig”. So, they need to do a lot more than just add kale to their menu before I’d ever eat there. The problem is that millions are still eating there and consuming several questionable food additives that McDonald’s could remove entirely if they really wanted to.

Explanation:

7 0
2 years ago
Which part of a machine control unit interacts with the machine tools through electric signals?=]
FrozenT [24]

Answer:

control loop unit

Explanation:

Edmentum/Plato

4 0
3 years ago
Steam enters a turbine steadily at 7 MPa and 600°C with a velocity of 60 m/s and leaves at 25 kPa with a quality of 95 percent.
Rufina [12.5K]

Answer:

a) \dot m = 16.168\,\frac{kg}{s}, b) v_{out} = 680.590\,\frac{m}{s}, c) \dot W_{out} = 18276.307\,kW

Explanation:

A turbine is a steady-state devices which transforms fluid energy into mechanical energy and is modelled after the Principle of Mass Conservation and First Law of Thermodynamics, whose expressions are described hereafter:

Mass Balance

\frac{v_{in}\cdot A_{in}}{\nu_{in}} - \frac{v_{out}\cdot A_{out}}{\nu_{out}} = 0

Energy Balance

-q_{loss} - w_{out} + h_{in} - h_{out} = 0

Specific volumes and enthalpies are obtained from property tables for steam:

Inlet (Superheated Steam)

\nu_{in} = 0.055665\,\frac{m^{3}}{kg}

h_{in} = 3650.6\,\frac{kJ}{kg}

Outlet (Liquid-Vapor Mix)

\nu_{out} = 5.89328\,\frac{m^{3}}{kg}

h_{out} = 2500.2\,\frac{kJ}{kg}

a) The mass flow rate of the steam is:

\dot m = \frac{v_{in}\cdot A_{in}}{\nu_{in}}

\dot m = \frac{\left(60\,\frac{m}{s} \right)\cdot (0.015\,m^{2})}{0.055665\,\frac{m^{3}}{kg} }

\dot m = 16.168\,\frac{kg}{s}

b) The exit velocity of steam is:

\dot m = \frac{v_{out}\cdot A_{out}}{\nu_{out}}

v_{out} = \frac{\dot m \cdot \nu_{out}}{A_{out}}

v_{out} = \frac{\left(16.168\,\frac{kg}{s} \right)\cdot \left(5.89328\,\frac{m^{3}}{kg} \right)}{0.14\,m^{2}}

v_{out} = 680.590\,\frac{m}{s}

c) The power output of the steam turbine is:

\dot W_{out} = \dot m \cdot (-q_{loss} + h_{in}-h_{out})

\dot W_{out} = \left(16.168\,\frac{kg}{s} \right)\cdot \left(-20\,\frac{kJ}{kg} + 3650.6\,\frac{kJ}{kg} - 2500.2\,\frac{kJ}{kg}\right)

\dot W_{out} = 18276.307\,kW

6 0
3 years ago
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