A. All the answers are correct (All of the above).
Answer:
Total no. of ways to line up cars is 20! = 2.43 c 10^18
Probability that the cars alternate is 0.00001 or 0.001%
Explanation:
Since, the position of a car is random.Therefore, number ways in which cars can line up is given as:
<u>No. of ways = 20! = 2.43 x 10^18</u>
For the probability that cars alternate, two groups will be formed, one consisting of US-made 10 cars and other containing 10 foreign made. The number of favorable outcomes for this can be found out as the arrangements of 2! between these groups multiplied by the arrangements of 10! for each group, due to the arrangements among the groups themselves.
Favorable Outcomes = 2! x 10! x 10!
Thus the probability of event will be:
Probability = Favorable Outcomes/Total No. of Ways
Probability = (2! x 10! x 10!)/20!
<u>Probability = 0.00001 = 0.001%</u>
Answer:
A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.
Explanation:
Answer:
Connect your computer to the OBD(On-Board Diagnostics) port and see whats wrong
Explanation:
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