Asolid rectangular rodhas a length of 90mm, made of steel material (E =207,000 MPa, Syield= 300 MPa), the cross section of the r
od is shownbelow.If the boundary conditions are fixed-freeand a safety factor of 2 on loadis required, (1)Find themaximumallowable load (Pallowable)on the rod. [9points]{hint: Pallowable= Pcr/required safety factor}(2)If the same critical load (Pcr) calculated from (1)above(Pcrisalready taken into accounta safety factor of 2)is applied to a solid round rodunderthe same boundary conditions, what is the minimum required diameter of the rod against buckling? [9points]
1 answer:
Answer:
13.6mm
Explanation:
We consider diameter to be a chord that runs through the center point of the circle. It is considered as the longest possible chord of any circle. The center of a circle is the midpoint of its diameter. That is, it divides it into two equal parts, each of which is a radius of the circle. The radius is half the diameter.
See attachment for the step by step solution of the problem
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Answer:
44.95 tonnes
Explanation:
According to principle of buoyancy the object will just sink when it's weight is more than the weight of the liquid it displaces
It is given that empty weight of box = 40 tons
Let the mass of the stones to be placed be = M tonnes
Thus the combined mass of box and stones = (40+M) tonnes..........(i)
Since the box will displace water equal to it's volume V we have
Now the weight of water displaced = is density of water = 1000kg/
Thus weight of liquid displaced = ..................(ii)
Equating i and ii we get
40 + M = 84.95
thus Mass of stones = 44.95 tonnes
Complete Question
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Answer:
The probability is
Explanation:
The explanation is shown on the second and third uploaded image
