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11Alexandr11 [23.1K]
3 years ago
5

A solid square rod is cantilevered at one end. The rod is 1 m long and supports a completely reversing transverse load at the ot

her end of ±1.5 kN. The material is AISI 1080 hot-rolled steel. If the rod must support this load for 4 × 104 cycles with a design factor of 1.5, what dimension should the square cross section have? Neglect any stress concentrations at the support end.

Engineering
1 answer:
algol133 years ago
4 0

Answer:

Explanation:

Find attached the solution

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a metal coin has certain properties that can be measured.which property of a coin is different on the moon that is on earth?
Sloan [31]

Answer:

Coins weigh less on the Moon.

Explanation:

Gravity is only 1/6th as strong on the Moon than it is on Earth. Where a nickle is about 5 grams on Earth, it is less than 1 gram on the Moon. Gravity is affected by the size of the planet or moon. The Moon is much less massive than the Earth.

8 0
3 years ago
1. Asbestos can be dangerous but is not a known carcinogen.<br> A) O True<br> B) O False
Leya [2.2K]
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3 years ago
How nany degrées is the included angle of General Purpose Acme threads? A. 60 B. 29 c. 14.5 D. 10
horrorfan [7]

Answer:

B.29

Explanation:

In general purpose acme thread:

  Nominal depth of thread=0.5ltimes Pitch

  Included angle =29 degrees

Generally Acme thread are following types

  1.General purpose(G) Acme

  2.Centralizing(C) Acme

  3. Stub Acme  

Centralizing(C) Acme threads have tighter tolerance during manufacturing as compare to General purpose(G) Acme  threads.

8 0
3 years ago
Calculate total hole mobility if the hole mobility due to lattice scattering is 50 cm2 /Vsec and the hole mobility due to ionize
Ad libitum [116K]

Answer:

The total hole mobility is 41.67 cm²/V s

Explanation:

Data given by the exercise:

hole mobility due to lattice scattering = ul = 50 cm²/V s

hole mobility due to ionized impurity = ui = 250 cm²/V s

The total mobility is equal:

\frac{1}{u} =\frac{1}{ul} +\frac{1}{ui} \\\frac{1}{u}=\frac{1}{50} +\frac{1}{250} \\u=41.67cm^{2} /Vs

5 0
3 years ago
Read 2 more answers
A good rule of thumb is to design the horizontal stabilizer so that its area is about 1/6 to 1/8 of the area of the wing. If the
erik [133]

Answer:

Stabilizer with area = 14 cm2

Explanation:

i dont know why but its right

4 0
3 years ago
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