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Lena [83]
2 years ago
12

. In any energy transformation, energy is _____. destroyed created conserved

Physics
2 answers:
zubka84 [21]2 years ago
8 0

Answer: i believe it is conserved or stays the same.

Explanation: energy cant be destroyed no matter what and no energy is being created

I hope this helps a thank and a brainlist would be greatly appreciated

Mrac [35]2 years ago
6 0

Answer: Nor

Explanation: In any energy transformation, energy is nor created destroyed or conserved

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Humans first traveled to the Moon in a spacecraft in 1969. What happened as the spacecraft traveled farther from Earth?
horsena [70]

Answer:

The answer is C)The force of gravity from Earth acting on the spacecraft decreased because the distance from Earth increased.

Explanation:

Gravity, a force, is dependent on the mass of the object exerting the gravity and the distance of an outside object from that object. The larger the object, the more gravity it will exert on an outside object. This force decreases as you move away from the object, but it will always still exist and never be equal to 0.

4 0
3 years ago
Read 2 more answers
A cart of mass m = 0.12 kg moves with a speed v = 0.45 m/s on a frictionless air track and collides with an identical cart that
lina2011 [118]

Answer:

0.006075Joules

Explanation:

The final kinetic energy of the system is expressed as;

KE = 1/2(m1+m2)v²

m1 and m2 are the masses of the two bodies

v is the final velocity of the bodies after collision

get the final velocity using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

0.12(0.45) + 0/12(0) = (0.12+0.12)v

0.054 = 0.24v

v = 0.054/0.24

v = 0.225m/s

Get the final kinetic energy;

KE = 1/2(m1+m2)v

KE = 1/2(0.12+0.12)(0.225)²

KE = 1/2(0.24)(0.050625)

KE = 0.12*0.050625

KE = 0.006075Joules

Hence the final kinetic energy of the system is 0.006075Joules

5 0
2 years ago
A 5.0-μC charge is placed at the 0 cm mark of a meter stick and a -4.0 μC charge is placed at the 50 cm mark. At what point on a
Maksim231197 [3]

Answer:

The distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

Explanation:

Given that

q₁ = 5 μ C

q₂ = - 4 μ C

The distance between charges = 50 cm

d= 50 cm

Lets take at distance x from the charge μ C ,the electrical field is zero.

That is why the distance from the charge - 4 μ C =  50 - x cm

We know that ,electric field is given as

E=K\dfrac{q}{r^2}

K\dfrac{5\ \mu}{x^2}=K\dfrac{4\mu }{(50-x)^2}\\\\\dfrac{5}{x^2}=\dfrac{4 }{(50-x)^2}\\\\\\5(50-x)^2=4x^2\\(50-x)^2=0.8x^2\\\\50-x =0.89x\\\ x=\dfrac{50}{1.89}\ cm\\\\\\x=26.45\ cm\\

Therefore the distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

3 0
3 years ago
A 25 n object requires a 5.0 n to start moving over a horizontal surface. what is the coefficient of static friction?
olganol [36]
Static friction is the friction that exists between two or more solids that are not moving with a relative speed. To calculate the static friction coefficient we use the formula Fs=us × n where Fs is the static friction , us is the coefficient of static friction and the n is the normal force.
thus the coefficient of static friction will be 5 N÷ 25 N =  0.2
Hence 0.2 is the coefficient of static friction
3 0
3 years ago
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1.Which of the following is evidence that the Earth is round?
PtichkaEL [24]

Answer:

1\D. Both A and C

2\A true

5 0
3 years ago
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