"LEO the lion goes GER" means based upon the oxidation and reduction reactions.
<h3>What is oxidation and reduction reaction?</h3>
Oxidation reactions are those reactions in which lossing of electrons are taking place from the substrate molecule and in reduction process gaining of electrons is done by substrate molecules.
The phrase "LEO the lion goes GER" is used in the context of oxidation and reduction reactions. Meaning of the terms:
LEO → Lose electrons = oxidation
GER → Gain electrons = reduction
Hence the given line is based on oxidation and reduction.
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Answer:
AX+BY=AY+BX
Explanation:
Double-replacement reactions are represented by the general equation AX+BY=AY+BX a reaction in which a substance combines with oxygen, releasing a large amount of energy in the form of light and head
Answer:
Supersaturated.
Explanation:
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In this case, according to this solubility chart, we infer that for NH3, the solubility starts at 90 grams of NH3 that are soluble in 100 g of water at 0 °C and ends in about 8 g in 100 g of water at 100 °C for a saturated solution.
However, since we are asked for the solubility of NH3 at 20 °C, we can see that, according to the table and the curve for NH3, about 52 g of NH3 are soluble in 100 g of water; thus, for the given 60 g of NH3, we will say that 8 grams will remain undissolved, and therefore, this solution will be supersaturated.
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Answer:
A . 2 O₃(g) + 2 NO ⇒ 2 O₂ (g) + 2 NO₂(g)
B . Yes
C. O and NO₃
Explanation:
A. The overall reaction is obtained by adding the individual steps in the reaction mechanism where we will get the reactants and product and the intermediates will cancel.
Thus, adding 1+ 2 +3 we get
2 O₃(g) + 2 NO ⇒ 2 O₂ (g) + 2 NO₂(g)
B. The reaction intermediates are those that are produced from the initial and/or subsequent steps and are consumed later on in the reaction mechanism, but are neither reactants nor products, they just participate.
From this definition it follows that O(g) and NO₃ are reaction intermediates.
C. O and NO₃
Answer:
38.75 L
Explanation:
From the question,
Applying Boyles Law,
PV = P'V'....................... Equation 1
Where P = Original pressure of the Argon gas, V = Original Volume of Argon gas, P' = Final pressure of Argon gas, V' = Final Volume of Argon gas.
make V the subject of the equation
V = P'V'/P.................... Equation 2
Given: P = 34.6 atm, V' = 456 L, P' = 2.94 atm.
Substitute these values into equation 2
V = (456×2.94)/34.6
V = 38.75 L
