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sweet-ann [11.9K]
2 years ago
11

Calculate the following expression and round your answer to the correct number of significant figures.

Chemistry
1 answer:
Butoxors [25]2 years ago
3 0

Answer:

63.9 cm

Explanation:

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*<br> Identify the element found in the f-block.<br> Cm<br> K<br> W<br> Br<br> Ag
shutvik [7]
Text me I don’t understand your question?
4 0
3 years ago
How many moles of O2 are produced when 0.425 mol of KO2 reacts in this fashion
Oksi-84 [34.3K]
The chemical reaction is expressed as:

<span> 4KO2+2CO2→2K2CO3+3O2 
</span>
We are given the amount of KO2 to be used in the reaction. This will be the starting point of our calculations. We do as follows:

0.425 mol KO2 ( 3 mol O2 / 4 mol KO2 ) = 0.319 mol O2 produced

Hope this answers the question. Have a nice day.
4 0
3 years ago
Molar mass (NH4)2SO4
Hoochie [10]

Answer:

<u>132.15</u>

Explanation:

Molar mass N = 14.00

Molar mass H = 1.01

Molar mass H4 = 1.01 x 4 = 4.04

Molar mass NH4 = 14.00 + 4.04 = 18.04

Molar mass (NH4)2 = 18.04 x 2 = 36.08

Molar mass S = 32.07

Molar mass O = 16.00

Molar mass O4 = 16.00 x 4 = 64.00

Molar mass SO4 = 32.07 + 64.00 = 96.07

Molar mass (NH4)2SO4 = 36.08 + 96.07 = <u>132.14</u>

6 0
3 years ago
Compare the seasons on Titan to the seasons on Earth.
kiruha [24]
Since Titan orbits roughly along Saturn's equatorial plane, and Titan's tilt relative to the sun is about the same as Saturn's, Titan's seasons are on the same schedule as Saturn's—seasons that last more than seven Earth years, and a year that lasts 29 Earth years.
6 0
2 years ago
In a coffee cup calorimeter, 1.60 g of NH4NO3 is mixed with 75.0 g of water at an initial temperature of 25.00 degrees C. After
igomit [66]

Answer:

+26.6kJ/mol

Explanation:

The enthalpy of dissolution of NH₄NO₃ is:

NH₄NO₃(aq) + ΔH  → NH₄⁺ + NO₃⁻

Where ΔH is the heat of reaction that is absorbed per mole of NH₄NO₃,

The moles that reacts in 1.60g are (Molar mass NH₄NO₃:80g/mol):

1.60g * * (1mol / 80g) = 0.02 moles reacts

To find the heat released in the coffee cup calorimeter, we must use the equation:

Q = m×ΔT×C

Where Q is heat released,

m is mass of the solution

ΔT is change in temperature (Final temperature - Initial temperature)

C is specific heat of the solution (4.18J/g°C)

Mass of the solution is:

1.60g + 75g = 76.60g

Change in temperature is:

25.00°C - 23.34°C = 1.66°C

Replacing:

Q = m×ΔT×C

Q = 76.60g×1.66°C×4.18J/g°C

Q = 531.5J

This is the heat released per 0.02mol. The heat released per mole (Enthalpy change for the dissolution of NH₄NO₃) is:

531.5J / 0.02mol = 26576J/ mol =

+26.6kJ/mol

<em>+ because the heat is absorbed, the reaction is endothermic-</em>

7 0
3 years ago
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