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2 years ago

Can someone check my answer? Is it B? Thanks!

Mathematics

2 answers:

zloy xaker [14]2 years ago

8 0

Solution is where the 2 lines intersect

I would say the answer is 3rd option, whre both lines pass through that point

koban [17]2 years ago

4 0

Answer:

(1, 4), because both lines pass through this point

Step-by-step explanation:

i just took the test

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I need with this question please. Please help me

klemol [59]

Answer:

idk

Step-by-step explanation:

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3 years ago

What would be the answer to 5/4 + 2/-9? How would you solve that? And if you could, could u leave the steps and then put the ans

Gemiola [76]

Answer: 37/36

Step-by-step explanation: find the lowest common multiples of 4 and -9 and the answer is -36

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3 years ago

Each day, a salesperson earns $25 plus 5% of their total sales for the day. The salesperson's goal is to earn more than $50 on T

uysha [10]

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2 years ago

Which of the following are like terms?

SVETLANKA909090 [29]

Answer: D) 13y^25 and 2y^25

Like terms involve the same variables, and each of those variables must have the same exponents.

Another example of a pair of like terms would be 5x^3y^2 and 7x^3y^2. Both involve the variable portion "x^3y^2" which we can replace with another variable, say the variable z. That means 5x^3y^2 becomes 5z and 7x^3y^2 becomes 7z. After getting to 5z and 7z, it becomes more clear we have like terms.

5 0

3 years ago

Solve the equation without the use of a calculator. please Help!!! Thank you!!!<br> 12x^3-30x=5-2x^2

nata0808 [166]

So, since we have a cubic equation with 4 terms, the first thing we should try is factoring by grouping, so:

$12x^3+2x^2-30x+5 =0 \implies \\ 2x^2(6x+1)-5(6x+1)=0 \implies \\ (2x^2-5)(6x+1) = 0$

Now that we've factored our equation, we can use ZPP and break it up:

$2x^2-5 = 0 \implies \\ 2x^2=5 \implies\\ x^2=\frac{5}{2} \implies\\ x=\pm\frac{\sqrt{5}}{\sqrt{2}}=\pm\frac{\sqrt{10}}{2} \\ \\ 6x+1 =0 \implies \\ 6x=-1 \implies\\ x=\frac{-1}{6}$

So, our solutions are:

$x\in \{\frac{\sqrt{10}}{2},-\frac{\sqrt{10}}{2},-\frac{1}{6}\}$

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3 years ago