Step by step solution: The position of hydrogen is controversial in the periodic table because hydrogen is the only element without neutrons. Hydrogen is a nonmetal and is placed above the group in the periodic table because it has ns1 electron configuration like the alkali metals.
Answer:
The four quantum number for each electron will be:
Explanation:
As the element is neutral, the number of protons will be equal to number of electrons which will be the atomic number of the element.
Number of electrons =12
Atomic number = 12
Element : Magnesium
The principal shell is represented by "n"
i) For "s" subshell the value of l =0 (azimuthal quantum number) thus m (magnetic quantum number)= 0
The two electrons in s subshell will have either plus half or minus half spin quantum number
ii) for "p" subshell the value for l =1
thus m = 0 or +1 or -1
The two electrons in each orbital will have either plus half or minus half spin quantum number
Formation of ammonia by nitrogen and hydrogen is habers process wher 28g N2 results in formation of 34g NH3
so 35g N2 will form 34*35/28=42.5g NH3 where it given that reaction takes place in excess of H2
N2+3H2 gives 2NH3
Answer:
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Answer:
4190.22 L = 4.19 m³.
Explanation:
- For the balanced reaction:
<em>2P₂ + 5O₂ ⇄ 2P₂O₅. </em>
It is clear that 2 mol of P₂ react with <em>5 mol of O₂ </em>to produce <em>2 mol of P₂O₅.</em>
- Firstly, we need to calculate the no. of moles of 6.92 kilograms of P₂O₅ produced through the reaction:
no. of moles of P₂O₅ = mass/molar mass = (6920 g)/(283.88 g/mol) = 24.38 mol.
- Now, we can find the no. of moles of O₂ is needed to produce the proposed amount of P₂O₅:
<u><em>Using cross multiplication:</em></u>
5 mol of O₂ is needed to produce → 2 mol of P₂O₅, from stichiometry.
??? mol of O₂ is needed to produce → 24.38 mol of P₂O₅.
∴ The no. of moles of O₂ needed = (5 mol)(24.38 mol)/(2 mol) = 60.95 mol.
- Finally, we can get the volume of oxygen using the general law of ideal gas:<em> PV = nRT.</em>
where, P is the pressure of the gas in atm (P = 606.1 mm Hg/760 = 0.8 atm).
V is the volume of the gas in L (V = ??? L).
n is the no. of moles of the gas in mol (n = 60.95 mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (396.90°C + 273 = 669.9 K).
∴ V of oxygen needed = nRT/P = (60.95 mol)(0.0821 L.atm/mol.K)(669.9 K)/(0.8 atm) = 4190.22 L/1000 = 4.19 m³.
