The answer is covalent bond!
Answer:
D. 1s2,2s2,2p6,3s2,3p6,3d10,4s2,4p6,4d10,5s2,5p6
Explanation:
Hello!
In this case, since the standard iodine atom has 53 electrons, when it forms the iodide ion it is known it gains one spare electron so now it has 54; it means we need to write the new electron configuration up to 54 as shown below:
Thus, the answer should be:
D. 1s2,2s2,2p6,3s2,3p6,3d10,4s2,4p6,4d10,5s2,5p6
Even when the order is not the adequate one.
Regards!
Answer:
Explanation:
2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O
n/mol: 4.3
13 mol of O₂ react with 2 mol of 2C₄H₁₀
One propertie is that it's round.