An object dropped on Planet P falls 144 m in 6 seconds. What is the gravitational acceleration of Planet P ? Gravitational accel
1 answer:
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<u>Answer:</u>
<em>The initial distance between the trains is 1450 m. </em>
<u>Explanation:</u>
In the question two trains are of equal length 400 m and moves at a uniform speed of 72 km/h. train A is moving ahead of train B. If the train B has to overtake train A it should accelerate.
Train B’s acceleration is and it accelerated for 50 seconds.
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<em>t=50 s </em>
<em>initial speed u=72km/h </em>
<em>we have to convert this speed into m/s </em>
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<em>Distance covered in accelerating phase </em>
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If a train is just behind another, the distance covered by the train located behind during overtaking phase will be equal to the sum of the lengths of the trains.
<em>Here length of train A+length of train </em>
<em>Hence the initial distance between the trains = </em>
Answer:
a)
b)
c)
d) Displacement = 22 m
e) Average speed = 11 m/s
Explanation:
a)
Notice that the acceleration is the derivative of the velocity function, which in this case, being a straight line is constant everywhere, and which can be calculated as:
Therefore, acceleration is
b) the functional expression for this line of slope 4 that passes through a y-intercept at (0, 3) is given by:
c) Since we know the general formula for the velocity, now we can estimate it at any value for 't", for example for the requested t = 1 second:
d) The displacement between times t = 1 sec, and t = 3 seconds is given by the area under the velocity curve between these two time values. Since we have a simple trapezoid, we can calculate it directly using geometry and evaluating V(3) (we already know V(1)):
Displacement =
e) Recall that the average of a function between two values is the integral (area under the curve) divided by the length of the interval:
Average velocity =