Answer:
Faraday's Law
Explanation:
Faraday’s Law of Induction explains how an electric current produces a magnetic field and also, how a changing magnetic field generates an electric current in a conductor.
While Faraday's law explains how magnitude of the EMF is produced, Lenz's law explains the direction that current will flow. The lenz's law states that the direction is always in a way which it will oppose the change in flux which produced it. Lenz's law simply explains that any magnetic field produced by an induced current will be in the opposite direction to the change in the original field.
In this lab, they are clearly making use of Faraday's law because they are inducing a current due to changes in magnetic flux. This situation involves Faraday's law because in Faraday's law, the induced magnetic field inside a loop will always move to keep the magnetic flux in the loop constant.
Answer: 6611.715 joules
Explanation:
Q = MxCxdeltaT = 6959.7 which is 100%
95% = 6611.715
Answer:
Fluid pressure from gravity is the weight of the fluid above divided by the area it is pushing on. Fluid pressure applies in all directions. Internal pressure of an object equals the external fluid pressure, otherwise the object could be crushed. Wind and heating can also create pressure.
Explanation:
Answer:
The moment of inertia is 
Explanation:
The moment of inertia is equal:

If r is 
and 


Answer:

Explanation:
The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.