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ra1l [238]
3 years ago
13

If the light bulb in the lava lamp had a lower wattage, what changes would you expect to see in the lava lamp. what if the lava

lamp had a higher wattage?
Physics
2 answers:
bixtya [17]3 years ago
8 0

Answer:

By energy efficient, if you mean LED, no the lamp will not flow like normal. If the bulb is still an incandescent but slightly lower wattage, it will take a little longer to get going. Lava lamps require heat and light for the effect to work.

Anettt [7]3 years ago
4 0
Trick question: lava lamps don’t have lightbulbs :)
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The initial volume reading in a graduated cylinder is 30 mL. The mass of an irregular shape of an unknown metal piece is 55.3 g.
Vadim26 [7]

Answer:

7.9\frac{gr}{cm^3}

Explanation:

When we put the metal piece in the liquid (which is in the graduated cylinder), how much it goes up is equal to the volume of the piece we inserted.

So now we know that the volume of that piece of unknown metal is 7mL (which is the same as 7cm^3).

Density is \frac{mass}{volume}.

So the density of that piece of metal is \frac{55.3g}{7cm^3}

Which leaves us with a final density of 7.9\frac{gr}{cm^3}

6 0
3 years ago
What is an indicator?
valkas [14]
The answer is A because An Indicator" changes color when it comes in contact with an acid or a base

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Two individuals start the same training program at the same time, but one is able to grow muscle faster and larger than the othe
vitfil [10]
I believe the answer is A
7 0
3 years ago
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Look at the circuit diagram. Which of these components is part of the circuit?
Roman55 [17]

Answer:

b ac power source

Explanation:

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7 0
3 years ago
What is the impulse of a 3 kg object that starts from rest and moves to 20 m/s?
IrinaK [193]

Answer:

The impulse on the object is 60Ns.

Explanation:

Impulse is defined as the product of the force applied on an object and the time at which it acts. It is also the change in the momentum of a body.

F = m a

F = m(\frac{v_{2}  - v_{1} }{t})

⇒     Ft = m(v_{2} - v_{1})

where: F is the dorce on the object, t is the time at which it acts, m is the mass of the object, v_{1} is its initialvelocity and v_{2} is the final velocity of the object.

Therefore,

impulse = Ft = m(v_{2} - v_{1})

From the question, m = 3kg, v_{1} = 0m/s and v_{2} = 20m/s.

So that,

Impulse = 3 (20 - 0)

             = 3(20)

             = 60Ns

The impulse on the object is 60Ns.

8 0
3 years ago
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