All categories

3 years ago

I need help on this equation, I tried multiplying but it didn’t work.

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

8 0

Your answer is C. Multiply $28.79x72. You will get $2,072.88. In the question it says “about” how much, so you are estimating. So round up to $2,100.00.

You might be interested in

Monica’s current office is a square. Her office in the company’s new building will be 3 feet wider and 5 feet longer

gregori [183]

Answer:

<h2> The are of the office is 15ft^2</h2>

Step-by-step explanation:

This problem is on the mensuration of flat shapes, this time on the square shape of an office.

given that

length of the office= 5 feet

width of the office= 3 feet

we can continue y solving for the area of the office, seeing that the information given by the question is just enough for the area

area of square= lenght* width

area= 5*3

area= 15 ft^2

The are of the office is 15ft^2

7 0

3 years ago

Alex buys a car with a down payment along with a monthly payment. if he pays $5,250 for the down payment, pays the monthly payme

svp [43]

Alex will pay $600 per month
13,650 -5,250= 8400
8400÷ 14= 600

4 0

3 years ago

Which expression is equivalent to 24 Superscript one-third

Tems11 [23]

Answer:

The expression that is equivalent is 2 RootIndex 3 StartRoot 3 EndRoot :

$2\sqrt[3]{3}$

Step-by-step explanation:

As we have 24 Superscript one-third, this is $(24)^{\frac{1}{3}} =\sqrt[3]{24}$ .

$\sqrt[3]{24}=\sqrt[3]{8*3}=\sqrt[3]{8} \sqrt[3]{3}$ , therefore

$\sqrt[3]{8} =2$ , so $\sqrt[3]{8} \sqrt[3]{3}=2\sqrt[3]{3}$ .

3 0

3 years ago

The number line shows the graph of an inequality:

Minchanka [31]

5 halves left from 0 is -2.5
-3.5 is further left than -2.5 so B

6 0

3 years ago

Which expression is equivalent to (a^-3 b/a^-5 b3)^-3? Assume a=0, b=0.

prohojiy [21]

$Use:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\\\(ab)^n=a^nb^n$

$\left(\dfrac{a^{-3}b}{a^{-5}b^3}\right)^{-3}=\left(a^{-3-(-5)}b^{1-3}\right)^{-3}=\left(a^{-3+5}b^{-2}\right)^{-3}=\left(a^2b^{-2}\right)^{-3}\\\\=(a^2)^{-3}(b^{-2})^{-3}=a^{2(-3)}b^{-2(-3)}=a^{-6}b^6=\dfrac{b^6}{a^6}$

7 0

3 years ago