Answer:
4.68x10⁹
Explanation:
Kp is the equilibrium constant based on presure, and depends only on the gas substances. For a generic equation:
aA(g) + bB(g) ⇄ cC(g) + dD(g)

The reaction given can be summed to form the third one:
C(s) + CO₂(g) ⇄ 2CO (g) K'p = 1.30x10¹⁴
CO(g) + Cl₂(g) ⇄ COCl₂ (g) K''p = 6.00x10⁻³
We need to multiply the second reaction by 2, so CO will be simplified. If we multiplied a reaction for n, the new Kp will be (Kp)ⁿ, so:
C(s) + CO₂(g) ⇄ 2CO (g) K'p = 1.30x10¹⁴
2CO(g) + 2Cl₂(g) ⇄ 2COCl₂(g) (K''p)²= (6.00x10⁻³)²
The Kp of the reaction resulted by the sum will be: Kp = K'p*K''p
C(s) + CO₂(g) + 2Cl₂(g) ⇄ 2CO(g) + 2COCl₂(g)
Kp = 1.30x10¹⁴ * (6.00x10⁻³)²
Kp = 1.30x10¹⁴*3.60x10⁻⁵
Kp = 4.68x10⁹
Answer:
The 5 chemical changes are. 1) Tarnish, 2) Rust, 3) Dissolve, 4) Burn, 5) Bake.
Salt water is a Homogeneous Mixture......
298 g of calcium carbonate CaCO₃
Explanation:
We have the following chemical reaction:
CaCN₂ (s) + 3 H₂O (l) → CaCO₃ (s)+ 2 NH₃ (g)
number of moles = mass / molar weight
number of moles of H₂O = 161 / 18 = 8.94 moles
Knowing the chemical reaction we devise the following reasoning:
if 3 moles of H₂O produces 1 mole of CaCO₃
then 8.94 moles of H₂O produces X moles of CaCO₃
X = (8.94 × 1) / 3 = 2.98 moles of CaCO₃
mass = number of moles × molar weight
mass of CaCO₃ = 2.98 × 100 = 298 g
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number of moles
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