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4 years ago

List two processes from which it may be concluded that the particles of a gas move continuously.

Chemistry

1 answer:

ziro4ka [17]4 years ago

5 0

Answer:

The two processes maybe:

One process can be the spread of smell of perfume . Tge particles of perfume mic in the air and reaches every corner of tge room because they are moving

Second can be the smell of food that reaches us in seconds . This case too tells that the aroma of the food particles gets intermixed and come to us .

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CH4 + 202 → CO2 + 2H2O<br> How many grams of O2 needed to react with 2 moles of CH4?

PtichkaEL [24]

<h3>Answer:</h3>

100 g O₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O

[Given] 2 mol CH₄

[Solve] x g O₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol CH₄ → 2 mol O₂

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

<u>Step 3: Stoichiometry</u>

Set up conversion: $\displaystyle 2 \ mol \ CH_4(\frac{2 \ mol \ O_2}{1 \ mol \ CH_4})(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})$
Multiply/Divide: $\displaystyle 128 \ g \ O_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

128 g O₂ ≈ 100 g O₂

3 0

3 years ago

Read 2 more answers

in which of the following aqueous solutions would you expect AgCl to have the HIGHEST solubility?a) Pure Waterb) 0.015 M NaClc)

kirill115 [55]

Answer:

Pure Water

Explanation:

The common ion effect describes the effect on equilibrium that occurs when a common ion (an ion that is already contained in the solution) is added to a solution. The common ion effect generally decreases solubility of a solute(Khan Academy).

NaCl, AgNO3, KCl, BaCl2 solutions all have a common ion with AgCl. As a result of this, AgCl will be much less soluble in these solvents than it is in pure water.

Therefore, AgCl will have the highest solubility in pure water compared to all the solutions listed above.

6 0

3 years ago

I’m so lost please help

Vadim26 [7]

d= 8/10 so yah that was a guess

8 0

3 years ago

What is the pH of a solution of 0.900 M KH2PO4, potassium dihydrogen phosphate? Express your answer numerically to the hundredth

stepan [7]

4.67 is the right answer

+ − − log(7,5 ∗ 10−3) − log(6.2 ∗ 10−8) ,34 ,24
= 2 = 2 =4.67

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3 years ago

Convert 22.0 mL to L

Ratling [72]

0.022

One milliliter is equal to a thousandth of a liter, so divide by 1000..

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4 years ago