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RSB [31]
3 years ago
5

A black squirrel is sitting on the ground. A red squirrel is sitting on a tree branch high above the black squirrel. Both squirr

els have the same mass. Compared to the red squirrel, the black squirrel has ______ kinetic energy and _______ gravitational potential energy.
Physics
2 answers:
labwork [276]3 years ago
4 0

The black squirrel has zero kinetic energy (if it's not moving) and lower gravitational potential energy than the red squirrel or zero gravitational potential energy if the ground is assumed to be zero gravitational potential line.

enot [183]3 years ago
4 0

Answer:

First blank is the same

Second blank is less

Explanation:

<u><em>hope i helped!</em></u>

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Velocity-time graph worksheet?
liq [111]

Answer: yep

Explanation:

6 0
3 years ago
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A dog uses 300 N of force to run 50 m with a speed of 5.9 m/s. How much power does he expand
balu736 [363]

Answer:

1.47kW

Explanation:

F = 300N, s = 50m, v = 5.9m/s

P = W/t

= (F× )/t

= F × v

= 300 × 5.9

= 1470Watt

= 1.47kW

6 0
4 years ago
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Help please ............
Solnce55 [7]

Answer:

47c

Explanation:

5 0
3 years ago
A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C.
Sedaia [141]

Answer:

335°C

Explanation:

Heat gained or lost is:

q = m C ΔT

where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.

Heat gained by the water = heat lost by the copper

mw Cw ΔTw = mc Cc ΔTc

The water and copper reach the same final temperature, so:

mw Cw (T - Tw) = mc Cc (Tc - T)

Given:

mw = 390 g

Cw = 4.186 J/g/°C

Tw = 22.6°C

mc = 248 g

Cc = 0.386 J/g/°C

T = 39.9°C

Find: Tc

(390) (4.186) (39.9 - 22.6) = (248) (0.386) (Tc - 39.9)

Tc = 335

7 0
3 years ago
just want to double-check that you understand a practical consequence of the expansion of the universe. Light reaches us from a
Daniel [21]

Answer:

<em>The distance of the light is 9.4608 x 10^25 m</em>

<em></em>

Explanation:

Time taken by the light = 10 billion years = 10 x 10^9 years

speed of light = 3 x 10^8 m/s

speed of light in m/years is = (3 x 10^8)/(60 x 60 x 24 x 365) = 9.4608 x 10^15 m/year

distance = speed x time

therefore, the distance of this light = 10 x 10^9 x 9.461 x 10^15 = <em>9.4608 x 10^25 m</em>

4 0
3 years ago
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