This question involves the concepts of orbital velocity and orbital radius.
The orbital velocity of ISS must be "7660.25 m/s".
The orbital velocity of the ISS can be given by the following formula:
where,
v = orbital velocity = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = Mass of Earth = 5.97 x 10²⁴ kg
R = orbital radius = radius of earth + altitude = 63.78 x 10⁵ m + 4.08 x 10⁵ m
R = 67.86 x 10⁵ m
Therefore,
<u>v = 7660.25 m/s</u>
Learn more about orbital velocity here:
Answer:
Option (c).
Explanation:
An object when when projected at an angle, will have some horizontal velocity and vertical velocity such that,
is the angle of projection
The horizontal component of the projectile remains the same because there is no horizontal motion. Vertical component changes at every point.
As a projectile falls, vertical velocity increases in magnitude, horizontal velocity stays the same .
Answer:
The angle between the blue beam and the red beam in the acrylic block is
Explanation:
From the question we are told that
The refractive index of the transparent acrylic plastic for blue light is
The wavelength of the blue light is
The refractive index of the transparent acrylic plastic for red light is
The wavelength of the red light is
The incidence angle is
Generally from Snell's law the angle of refraction of the blue light in the acrylic block is mathematically represented as
Where is the refractive index of air which have a value of
So
Generally from Snell's law the angle of refraction of the red light in the acrylic block is mathematically represented as
Where is the refractive index of air which have a value of
So
The angle between the blue beam and the red beam in the acrylic block
substituting values
Answer:
the question is incomplete, the complete question is
"A circular coil of radius r = 5 cm and resistance R = 0.2 ? is placed in a uniform magnetic field perpendicular to the plane of the coil. The magnitude of the field changes with time according to B = 0.5 e^-t T. What is the magnitude of the current induced in the coil at the time t = 2 s?"
2.6mA
Explanation:
we need to determine the emf induced in the coil and y applying ohm's law we determine the current induced.
using the formula be low,
where B is the magnitude of the field and A is the area of the circular coil.
First, let determine the area using where r is the radius of 5cm or 0.05m
since we no that the angle is at
we determine the magnitude of the magnetic filed
the Magnitude of the voltage is 0.000532V
Next we determine the current using ohm's law