Answer:
The answer to your question is 75%
Explanation:
Data
Theoretical production = 4 moles
Experimental production = 3 moles
Percent yield = ?
Formula

Substitution

Result
Percent yield = 75 %
Answer:
ΔSv = 0.1075 KJ/mol.K
Explanation:
Binary solution:
∴ a: solvent
∴ b: solute
in equilibrium:
- μ*(g) = μ(l) = μ* +RTLnXa....chemical potential (μ)
⇒ Ln (1 - Xb) = ΔG/RT
∴ ΔG = ΔHv - TΔSv
⇒ Ln(1 -Xb) = ΔHv/RT - ΔSv/R
∴ Xb → 0:
⇒ Ln(1) = ΔHv/RT - ΔSv/R
∴ T = T*b....normal boiling point
⇒ 0 = ΔHv/RT*b - ΔSv/R
⇒ ΔSv = (R)(ΔHv/RT*b)
⇒ ΔSv = ΔHv/T*b
∴ T*b = 80°C ≅ 353 K
⇒ ΔSv = (38 KJ/mol)/(353 K)
⇒ ΔSv = 0.1075 KJ/mol.K
Answer:
F₂ (g) + FeI₂ (aq) → FeF₂ (aq) + I₂ (l)
Explanation:
Our reactants are:
F₂ → Fluorine gas, a dyatomic molecule
FeI₂ → Iron (II) iodine
Our products are:
I₂ → Iodine
FeF₂ → Iron (II) fluoride
Then, the reaction is:
F₂ (g) + FeI₂ (aq) → FeF₂ (aq) + I₂ (l)
We see it is completely balanced.
Answer:
please refer to the attachment above;)
Answer:
Ca^+2
Explanation:
Hence, the correct option is A.