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Bad White [126]
4 years ago
6

If you have 30 amps, how much charge moves past a point in the circuit in 120 seconds.

Physics
1 answer:
dolphi86 [110]4 years ago
6 0
Q = I t = 30 x 120 = 3600 C
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An object with a mass M = 250 g is on a plane inclined at 30º above the horizontal and is attached by a string to a mass m = 150
malfutka [58]

Answer:

0.495 m/s

Explanation:

T = tension force in the string connecting the two objects

M = Mass of the object on inclined plane = 250 g = 0.250 kg

m = Mass of the hanging object = 150 g = 0.150 kg

a = acceleration of each object

From the force diagram, force equation for the motion of the object on the inclined plane is given as

T - Mg Sin30 = Ma\\T = Mg Sin30 + Ma

From the force diagram, force equation for the motion of the hanging object on the inclined plane is given as

mg - T = ma\\T = mg - ma

Using the above two equations

Mg Sin30 + Ma = mg - ma

(0.250)(9.8) Sin30 + (0.250) a = (0.150) (9.8) - (0.150)a

a = 0.6125 ms^{-2}

h = height dropped by the hanging object = 10 cm = 0.10 m

v = Speed gained by the object

Speed gained by the object can be given as

v = sqrt(2ah)\\v = sqrt(2(0.6125)(0.20))\\v = 0.495 ms^{-1}

5 0
3 years ago
What is congruence in science
aalyn [17]

Answer:

look it up on google

Explanation:

7 0
4 years ago
The potential (relative to infinity) at the midpoint of a square is 3.0 V when a point charge of +Q is located at one of the cor
Sveta_85 [38]

Answer:

d) 12 V

Explanation:

Due to the symmetry of the problem, the potential (relative to infinity) at the midpoint of the square, is the same for all charges, provided they be of the same magnitude and sign, and be located at one of the corners of the square.

We can apply the superposition principle (as the potential is linear with the charge) and calculating the total potential due to the 4 charges, just adding the potential due to any of  them:

V = V(Q₁) + V(Q₂) +V(Q₃) + V(Q₄) = 4* 3.0 V = 12. 0 V

4 0
3 years ago
The moon has a smaller mass than the Earth. If you were able to travel to the moon your weight would
Lelu [443]

Answer:

for example, a person weighing 100kg when on the moon only has 38kg is not wrong because the scale is just a device to measure weight, not mass, people have taken advantage of gravity to measure the weight of objects, so I think Your actual weight doesn't change, what changes is gravity and acceleration

Explanation:

3 0
3 years ago
Planets beyond the solar system.On October 15, 2001, a planet was discovered orbiting around the star HD68988. Its orbital dista
Evgesh-ka [11]

Answer:

Part a)

M = 2.31 \times 10^{30} kg

Part b)

M = 1.15 M_s

Explanation:

Part a)

As we know that the period of revolution of the planet is given by

T = 2\pi\sqrt{\frac{r^3}{GM}}

now we know that

r = 10.5 \times 10^6 km = 1.05 \times 10^{10} m

T = 6.3 days

T = 5.44 \times 10^5 s

now we have

5.44 \times 10^5 = 2\pi\sqrt{\frac{(1.05\times 10^{10})^3}{(6.67 \times 10^{-11})M}}

M = 2.31 \times 10^{30} kg

Part b)

As we know that mass of sun is given as

M_s = 2.0 \times 10^{30} kg

now we have

\frac{M}{M_s} = \frac{2.31 \times 10^{30}}{2 \times 10^{30}}

M = 1.15 M_s

6 0
4 years ago
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