I WILL MARK BRAINLIEST FOR THE CORRECT ANSWER

What is the wavelength in nm of a light whose first order bright band forms a

miskamm [114]

Answer:

714 nm

Explanation:

Using the equation: nλ=d<em>sin</em>θ

where

n= order of maximum

λ= wavelength

d= distance between lines on diffraction grating

θ= angle

n is 1 because the problem states the light forms 1st order bright band

λ is unknown

d= $\frac{1}{700,000}$ or 0.0000014 (meters)

sin(30)= 0.5

so

(1)λ=(0.0000014)(0.5)

=0.000000714m or 714 nm

3 0

3 years ago

What do hurricanes and tornadoes have in common

Hunter-Best [27]

strong winds

thunderstorms

rotating

4 0

3 years ago

Read 2 more answers

According to the fluid-mosaic model of a cell membrane, the main component of a membrane is...

Julli [10]

Answer:

The answer is C

Explanation:

A lipid bilayer makes up the cell membrane because it is more like a chain link fence that is flexible allowing cell movement.

7 0

4 years ago

Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is 21 ∘C∘C. Express the pressure

Volgvan

The question is incomplete, complete question is ;

A deep-sea diver uses a gas cylinder with a volume of 10.0 L and a content of 51.8 g of $O_2$ and 33.1 g of He. Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is 21°C.Express the pressures in atmospheres to three significant digits separated by commas.

Answer:

Partial pressure of the oxygen gas is 3.91 atm.

Partial pressure of the helium gas is 20.0 atm

Total pressure of the gases is 24.0 atm

Explanation:

Moles of oxygen gas = $n_1=\frac{51.8}{32 g/mol}=1.619 mol$

Moles of helium gas = $n_2=\frac{33.1 g}{4 g/mol}=8.275 mol$

Total moles of gas = $n_1+n_2=(1.619 +8.275 ) mole=9.894 mol$

Volume of the cylinder = V = 10.0 L

Total pressure in the cylinder = P = ?

Temperature of the gas in cylinder = T = 21°C = 21 + 273 K = 294 K

PV = nRT ( ideal gas equation )

$P=\frac{nRT}{V}$

$=\frac{9.894 mol\times 0.0821 atm L/mol K\times 294 K}{10.0 L}$

P = 23.88 atm ≈ 23.9

Partial pressure of the individual gas will be determined by the help of Dalton's law:

partial pressure = Total pressure × mole fraction of gas

Partial pressure of the oxygen gas

$p_{1}=P\times \chi_{1}=P\times \frac{n_1}{n_1+n_2}$

$p_1=23.88 atm\times \frac{1.619 mol}{9.894 mol}=3.91 atm$

Partial pressure of the helium gas

$p_{2}=P\times \chi_{2}=P\times \frac{n_2}{n_1+n_2}$

$p_2=23.88 atm\times \frac{8.275 mol}{9.894 mol}=19.97 atm\approx 20.0 atm$

6 0

4 years ago

The Solubility Product Constant for calcium bromide is > 1. If calcium bromide is dissolved in water you can say that the equ

DiKsa [7]

Answer: (1). If calcium bromide is dissolved in water you can say that the equilibrium concentrations of calcium and bromide ions are high.

(2). The solubility of calcium bromide in water is high.

Explanation:

We know that for a reaction its solubility product is equal to the product of concentration of ions present.

For example, $CaBr_{2} \rightarrow Ca^{2+} + 2Br^{-}$

$K_{sp} = [Ca^{2+}][Br^{-}]^{2}$

As it is given that for this reaction $K_{sp}$ > 1. Hence, the product of concentration of both these ions will be greater than 1 which means that products are favored.

Therefore, equilibrium concentrations of calcium and bromide ions are high.

Also, more is the number of these ions formed more will be the solubility of the compound ( $CaBr_{2}$ ).

As a result, the solubility of calcium bromide in water is high.

7 0

4 years ago