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kondaur [170]
4 years ago
9

Which of the following is an example of potential rather than kinetic energy?

Physics
1 answer:
adoni [48]4 years ago
3 0

Answer:

A molecule of glucose                                  

Explanation:

Kinetic energy is the energy possessed due to the motion of an object. Potential energy is the energy that is stored in the object. Out of given options, the example of potential energy is a molecule of glucose. When glucose breaks down, the energy is gets released in the form of ATP. Here, the glucose is static only is energy is getting stored in it.

Hence, the correct option is (b).

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Cual es la masa de los planetas, y la distancia que hay de la tierra a cada uno de ellos.
qwelly [4]

Answer:

Mercurio

Masa

3,285 × 10^23 kg

Mercurio está a una distancia promedio de 48 millones de millas (77 millones de kilómetros) de la Tierra.

Venus

Masa

4.867 × 10^24kg

En su punto más cercano a la Tierra, Venus está a unos 61 millones de kilómetros (38 millones de millas) de distancia.

tierra

Masa

5.972 × 10^24kg

Marte

Masa

6,39 × 10^23 kg

La distancia mínima de la Tierra a Marte es de unos 54,6 millones de kilómetros (33,9 millones de millas).

Júpiter

Masa

1.898 × 10^27kg

Debido a que ambos planetas viajan en una trayectoria elíptica alrededor del sol, la distancia de Júpiter a la Tierra cambia constantemente. Cuando los dos planetas están en su punto más cercano, la distancia a Júpiter es de solo 365 millones de millas (588 millones de kilómetros).

Saturno

Masa

5.683 × 10^26kg

Su distancia más cercana a la Tierra es de aproximadamente 1.200 millones de kilómetros (746 millones de millas)

Urano

Masa

8.681 × 10^25kg

la distancia entre la Tierra y Urano cambia diariamente. Lo más cerca que están los dos es 1.600 millones de millas (2.600 millones de kilómetros).

Neptuno

Masa

1.024 × 10^26kg

Cuando Neptuno y la Tierra se alinean en el mismo lado del sol, en su punto más cercano, están a solo 2,700 millones de millas (4,300 millones de kilómetros)

masa de Plutón =

1.30900 × 10^22 kilogramos

Plutón se encuentra a 4670 millones de millas (7500 millones de kilómetros) de la Tierra. En su punto más cercano, los dos están a solo 2660 millones de millas (4280 millones de km) de distancia.

8 0
3 years ago
It takes 40 J of energy to push a large box 4m across a floor. Assuming the push is the same direction as the movement, what is
Jobisdone [24]

Answer:

10 N

Explanation:

Work done is the dot product of the force magnitude with distance and cosine of the angle betweenthem.

Equation to use: W=|F|*|d|*cosθ

Your unknown is the force F; You have one equation, oneunknown.

40j=(F)*(4m)*cos(0)

F=40j/4m

F=10N

3 0
3 years ago
Read 2 more answers
An object at rest or moving at a constant speed in a straight path will continue to do so unless acted upon by an unbalanced for
Furkat [3]
I believe if your looking for true or false answer, that the answer is true
5 0
3 years ago
When you see a quantity like 20 m/s N, how do you know that it's a vector quantity and not a scalar quantity?
KengaRu [80]

We know that 20 m/s N is a vector quantity because N in the expression signifies the direction

<h3>What is a vector quantity?</h3>

This is a which have both magnitude and direction. Example include:

  • Velocity
  • Displacement
  • Force
  • Acceleration
  • Moment
  • Weight

<h3>How to determine whether 20 m/s N is a vector quantity</h3>
  • 20 m/s indicates just the speed i.e magnitude
  • 20 m/s N indicates the speed i.e magnitude why the N indicates the direction.

Thus, we can conclude that 20 m/s N is a vector quantity because it has both magnitude and direction.

Learn more about scalar and vector quantity:

brainly.com/question/774036

#SPJ12

5 0
2 years ago
In a game of pool the cue ball is rolling at 2.00 m / s in a direction 30.0° north of east when it collides with the eight ball
victus00 [196]

Answer:

v_{f1}=1.758m/s

v_{f1}=1.758m/s

Explanation:

The collision is elastic so we can use the conservation of momentum

P_i=P_f

m_1*v_1+m_2*v_2=m_1*v_{f1}+m_2*v_{f2}

Describe the motion in axis x'

170g*2.0m/s*cos(30)+156g*0m/s=170*cos(10)*v_{f1}+156g*0m/s

294.44 g*m/s=167.41g*v_{f1}

v_{f1}=1.758m/s

Describe the motion in axis y'

170g*2.0m/s*sin(30)=170g*1.75m/s*sin(10)+156*v_{f2}

v_{f2}=1.55m/s

7 0
4 years ago
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