Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
, 
Explanation:
From the question we are told that
The initial velocity of the arcade ball is 
The time taken by the ball to enter the basket is 
Generally the x -component of the initial velocity is
=> 
Generally the y -component of the initial velocity is
=> 
Generally the distance x is mathematically represented as
=> 
=>
Generally from kinematic equation the distance y is mathematically represented as
=> 
=>
Answer:
Charge on B is 12 uC.
Explanation:
Initial charge on A = 32 uC
Initial charge on B and C = 0
Now A touches to B, so the charge on A and B both is
q = (32 + 0) / 2 = 16 uC
Now A touches to C, so the charge on A and C both is
q' = (16 + 0) / 2 = 8 uC
Now again A touches to B so the charge on B is
q''= (8 + 16) / 2 = 12 uC
That every wave length of light except purple is being absorbed by the hat. The hat will be the color purple
Answer:
I would increase the horizontal velocity or the vertical velocity or both to make the ball go the extra distance to cross the goal line.
Explanation:
In order to increase the horizontal distance covered by the ball, we need to examine the variables involved in the formula of range of projectile. The formula for the range of projectile is given as follows:
R = V₀² Sin 2θ/g
where, g is a constant on earth (acceleration due to gravity) and θ is the angle of ball with ground at the time of launching. The value of θ should be 45° for maximum range. In this case we do not know the angle so, we can not tell if we should change it or not.
The only parameter here which we can increase to increase the range is launch velocity (V₀). The formula for V₀ in terms of horizontal and vertical components is as follows:
V₀ = √(V₀ₓ² + V₀y²)
where,
V₀ₓ = Horizontal Velocity
V₀y = Vertical Velocity
Hence, it is clear from the formula that we can increase both the horizontal and vertical velocity to increase the initial speed which in turn increases the horizontal distance covered by the ball.
<u>Therefore, I would increase the horizontal velocity or the vertical velocity or both to make the ball go the extra distance to cross the goal line.</u>
Answer:
a. 0.5307 sec
b. 0.4458 m
c. =
Explanation:
Horizontal Motion
It describes the dynamics of an object thrown horizontally in free air. The initial horizontal velocity is maintained all the time since no horizontal forces are acting. The initial vertical velocity is zero at launch time, but it grows downwards powered by the acceleration of gravity.
The object hits the ground at a distance x from the point of launching, after having traveled a vertical distance 
, taking a time t to complete the travel. The formulas who relate the different magnitudes are
The horizontal velocity 
is the same regardless of the elapsed time
The plate of apple pie left the counter at a speed
The counter is 
high.
a.
Knowing that
We use this formula to compute t
At the moment when the plate hits the floor y=0
Solving for t
b.
c.
