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yanalaym [24]
4 years ago
5

What is the equation of the line that passes through (5,-2) and (-3,4)

Mathematics
1 answer:
Gennadij [26K]4 years ago
3 0

Answer:

3x + 4y = 7

Step-by-step explanation:

The slope = difference of y values / corresponding difference in x values of the 2 points.

Here it  is (4 - (-2) / (-3 - 5)

= 6 /-8 = -3/4.

Now we use the point/slope form of the equation of a line:

y - y1 = m(x - x1)  where m = slope and (x1, y1) is a point on the line.

We take the point (5, -2) and m = -3/4:

y - (-2) = -3/4 (x - 5)

y + 2 = -3/4x + 15/4

y = -3/4 x + 15/4 - 8/4

y = -3/4 x + 7/4  This is the equation in slope/intercept form.

To convert it to standard form we multiply through by 4 and rearrange:

4y = -3x + 7

3x + 4y = 7  is standard form.

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4 years ago
Help for this question fr​
lesya692 [45]

Answer:

(x + 16)° = 141°

Step-by-step explanation:

  • Given figure is of octagon

  • Sum of interior angles of an octagon is 1080°

  • -> 5x° + 455° = 1080°

  • -> 5x° = 1080° - 455°

  • ->5x° = 625°

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6 0
3 years ago
6TH GRADE MATH<br> someone please solve this
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4 0
3 years ago
Read 2 more answers
What is the greatest prime you must consider to test whether 575 is prime
GuDViN [60]

Hello from MrBillDoesMath!

Answer:  23

Discussion:

We only need to check primes less that the square root of 576, which is about 23.98. As 23 is a prime number, it is the answer to the question.

Another way of looking at this: the primes less than or equal to 23

(23*23 = 529)

2, 3, 5,7,11,13,17,19,23

The greatest prime in the list is 23


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3 0
3 years ago
The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 330 grams and a standard deviati
just olya [345]

Answer:

Weights of at least 340.1 are in the highest 20%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 330, \sigma = 12

a. Highest 20 percent

At least X

100-20 = 80

So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.

Z = \frac{X - \mu}{\sigma}

0.842 = \frac{X - 330}{12}

X - 330 = 12*0.842

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Weights of at least 340.1 are in the highest 20%.

3 0
3 years ago
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