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Sonbull [250]
3 years ago
6

H4X - pKa1 =1.5

Chemistry
1 answer:
Nataly [62]3 years ago
8 0
Othu['oi;eejlktmkolhkjdfm;hojnor;'mor;'mor;'mor;'mor;'mor;'mhim

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if .709 j of heat is added to water and cause the temperature to go up by .036 degrees C what mass of water is present
liberstina [14]

Answer:

0.00471 grams H₂O

Explanation:

To determine the mass, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°C)

-----> ΔT = temperature change (°C)

The specific heat capacity of water is 4182 J/g°C. You can plug the given values into the equation and simplify to isolate "c".

Q = 0.709 J                            c = 4182 J/g°C

m = ? g                                   ΔT = 0.036 °C

Q = mcΔT                                                    <----- Equation

0.709 J = m(4182 J/g°C)(0.036 °C)            <----- Insert values

0.709 J = m(150.552)                                 <----- Multiply 4182 and 0.036

0.00471 = m                                              <----- Divide both sides by 150.552

8 0
1 year ago
Do you think that the government should regulate the sale or production of sugary drinks? Explain why or why not.
Fofino [41]

yrufbd brinckerhoff circ six

5 0
3 years ago
Which unit conversion allows you to convert 21.0 gallons into milliliters?
Ulleksa [173]

Answer:

Explanation:

we are given

there are in 0.073 gallons

we can see that there are two non-zero places after decimals

so, there are two siginificant figures

step-1: Change gallons to quarts

we know that

1 gallon = 4 quarts

so, we can write as

step-2: Change into liter

we know that

1 liter = 1.057 quarts

or

step-3: Change into millilitre

we know that

Since, it is asking for only two significant figures

so, we can also write as

...................Answer

3 0
3 years ago
Help name this, it’s chemistry
vova2212 [387]

Answer:

I believe it's

4-floro-5,6,8-Tribromo-3,3,7-trimethylnonane

5 0
2 years ago
6832 J of heat energy is applied to 5.9 mol of water. If the original temperature of the water was 18.60C, the final temperature
sineoko [7]

Answer: The final temperature of the water will be 34.0^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed=6832 Joules

m= mass of water = 5.9mol\times 18g/mol=106.2g

c = specific heat capacity = 4.184J/g^0C

Initial temperature of the water = T_i = 18.6^0C

Final temperature of the water = T_f  = ?

Putting in the values, we get:

6832=106.2\times 4.184\times (T_f-18.6)

T_f=34.0^0C

The final temperature of the water will be 34.0^0C

8 0
3 years ago
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