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adoni [48]
3 years ago
5

35.10 g of aluminum hydroxide is allowed to react with 53.94 g of sulfuric acid as follows:2Al(OH)3(s) + 3H2SO4(aq) -------->

Al2(SO4)3(aq) + 6H2O(l)What is the maximum mass of aluminum sulfate which could be produced in the reaction?
Chemistry
1 answer:
ikadub [295]3 years ago
8 0

Answer:

62.586 gram

Explanation:

moles of Al(OH)3 = mass / molar mass = 35.1 / (27+17x3) = 0.45 mol

moles of H2SO4 = mass / molar mass = 53.94 / (2+32+16x4) = 0.55 mol

H2SO4 is the limiting reagent (reacts completely)

⇒ moles of Al2(SO4)3 is worked out by moles of H2SO4

moles of Al2(SO4)3 = moles of H2SO4 / 3 = 0.183 mol

mass of Al2(SO4)3 = mole x molar mass = 0.183 x (27x2 + 96x3) = 62.586 gram

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Answer:

1.5x1024

Explanation:

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Strontium and chlorine combine in only one ratio: one strontium atom for every two chlorine atoms. Based on this
Vinvika [58]

The combinations of Strontium and chlorine  that are possible are only those in which strontium and chlorine combine in the ratio of 1:2.

1) The possible combinations are

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2) The combinations that are not possible are

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We have to work out the ratio of Strontium and chlorine in each of the given  combinations in the question. Only the combinations in which the ratio of Strontium and chlorine is 1:2 is possible.

First case:

4 strontium atoms and 8 chlorine atoms gives a Strontium and chlorine ratio of 1:2 so it is possible.

Second case:

20 strontium atoms and 60 chlorine atoms gives a Strontium and chlorine ratio of 1:3 hence it is not possible.

Third case:

2.7 * 10^19 strontium atoms and 5.4 * 10^19 chlorine atoms gives a Strontium and chlorine ratio of 1:2 hence it is possible.

Fourth case:

130 billion strontium atoms and 195 billion chlorine atoms gives a Strontium and chlorine ratio of 1:1.5 hence it is not possible.

Learn more: brainly.com/question/9743981

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Write the electron configuration of the element that has Z = 3 *
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Explanation:

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