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2 years ago

Integrated circuits typically are mounted on ________, which are then plugged into the system board.

Engineering

1 answer:

MrRa [10]2 years ago

5 0

Answer:

chip carriers

Explanation:

The components of a transistor or an integrated circuit are contained on a chip carrier. It is also frequently referred to as a chip container or chip package. With the help of this packaging, the chips can be connected or plugged into a circuit board without risking damage to their delicate components. As chip carriers have shrunk in size to accommodate new technologies, the procedure of installing them has grown more complicated.

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Answer:

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Explanation:

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3 years ago

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3 years ago

Three groups of students are given study outlines for 6 weeks. One group studies 2 hours a night, a second group studies 1 hour

katrin2010 [14]

Answer:

The constant here is the study outline

Explanation:

In scientific research, the constant variable is that part/variable of the experiment that does not change or is set not to change. Examples include temperature, environment or height.

Assuming the scenery described in this question is an experiment. All the groups presented are bound by a constant during the experiment. The constant here is the study outline. The study outline provided to the students is not going to change.

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3 years ago

I am standing on the upper deck of the football stadium. I have an egg in my hand. I am going to drop it and you are going to tr

Alina [70]

Answer:

Δx = 25 ft.

Explanation:

Assuming that the person on the ground starts running at the same time as the egg is dropped, we have two simultaneous trajectories:

1 ) Egg falling:

If the egg is dropped, and we neglect the air resistance, we can use the kinematic equation that relates the distance and fall time, as follows:

yf-y₀ = 1/2* g* t²

If we take the up direction as positive, we can solve for t as follows:

0-100 ft = 1/2* (-32.15 ft/s²)* t²

⇒ t = $\sqrt{(100*2)/32.15}$ = 2.5 sec.

2) Person on the ground running away:

In order to be able to run away, and then return to catch the egg, running at constant speed, he must run during exactly the half of the time that the egg is falling, i.e., 1.25 sec.

We can get the distance at which he can reach, applying the definition of velocity:

v = (xf-x₀) / (tfi-t₀)

If we choose t₀=0 and x₀ = 0 , we can solve for xf, as follows:

xf = v*t = 20 ft/sec*1.25 sec = 25 ft.

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3 years ago