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2 years ago

6

A school is playing $0.XY per kWh for electric power. To reduce its power bill, the school installs a wind turbine with a rated

power of 30 kW. If the turbine operates (2000 X) hours per year at the rated power. Determine the amount of electric power generated by the wind turbine and the money saved by the school per year.

1 answer:

Semmy [17]2 years ago

5 0

Answer: Your question has some missing figures so kindly plug in the values into the solution provided to get the exact amount of money saved

answer : Electric power generated = 216 * 10^6 kJ

money saved = $0.XY * 60000 kwh

Explanation:

<u>Calculating the amount of electric power generated by wind turbine</u>

power generated = ( 30 * 2000 ) kWh = 60000 kWh

Electric energy generated = 60000 kWh * 3600 kJ = 216 * 10^6 kJ

<u>Calculate money saved by school per year </u>

$0.XY * 60000 kwh

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Initially when 1000.00 mL of water at 10oC are poured into a glass cylinder, the height of the water column is 1000.00 mm. The w

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Hence the depth of the heated hot water is $\mathbf{h_2 =1021.9 \ mm}$

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