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3 years ago

14

you have two nickels three dimes and a quarter using at least one of each coin, how many different amounts of money can you make

? explain

1 answer:

alexgriva [62]3 years ago

8 0

5 different amount
3d 2n 1q=65cents
1d 1n 1q=40cents
2d 2n 1q=55cents
1d 2n 1g=45cents
3d 1n 1q=60cents

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What is the slope of a line that is perpendicular to the

alexgriva [62]

Answer:

The slope of a line that is perpendicular to the line

shown in the graph is = 4

Hence, option 'd' is true.

Step-by-step explanation:

From the line equation, let us take two points

(0, 2)

(4, 1)

Finding the slope between two points

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(0,\:2\right),\:\left(x_2,\:y_2\right)=\left(4,\:1\right)$

$m=\frac{1-2}{4-0}$

$m=-\frac{1}{4}$

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

The slope of the perpendicular line will be:

$-\frac{1}{-\frac{1}{4}}=4$

Thus, the slope of a line that is perpendicular to the line

shown in the graph is = 4

Hence, option 'd' is true.

5 0

3 years ago

Please help me understand this! Thanks a bunch if you help!

mariarad [96]

Segment BD equals 12<span />

6 0

3 years ago

10. If 1000 cm = 1 l, find the capacity of the following water tank in litre

Lelu [443]

<h2>Given :</h2>

length = 200 cm

breadth = 150 cm

height = 100 cm

<h2>Solution : </h2>

$\large \boxed{volume = l \times b \times h}$

$200 \times 150 \times 100$

$3000000 \: \: cm {}^{3}$

Through the statement above we have,

$\small\mathrm{1000 \: cm³ = 1 \: \: }l$

$\small\mathrm{1 \: cm {}^{3} = \dfrac{1}{1000} \: }l$

$\small\mathrm{3000000 \: cm {}^{3} = 3000000 \times \dfrac{1}{1000} \: }l$

$\small\mathrm{3000000 \: cm {}^{3} = 3000000 \times \dfrac{1}{1000} \: }l$

$\small\mathrm{ 3000 \: \: litres}$

_____________________________

$\mathrm{ \#TeeNForeveR}$

3 0

3 years ago

How long will it take a $800 investment to be worth $900 if it is continuously compounded at 11% per year?

Kruka [31]

The formula is
A=p e^rt
A future value 900
P present value 800
E constant
R interest rate 0.11
T time?

We need to solve for t
T=[log (A/p)÷log (e)]÷r
T=(log(900÷800)÷log(e))÷0.11
T=1.07 years round your answer to get 1 year

3 0

3 years ago

Pls helpppppp I really need helpppp

dem82 [27]

A and c are true ! I hope this helps

8 0

2 years ago