I’m pretty sure that it’s the third answer (q^12)! :)
Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
Answer:
d. 15-(-18)
Step-by-step explanation:
Take the second point and subtract the first point
15 - (-18)
15 + 18
33
Answer:
Step-by-step explanation:
According to the graph, the function h(x) is the translation of the function f(x) to the right and down.
Compare the coordinates of the vertices to write the formula
- x = 6 - (-6) = 12
- y = 7 - 11 = - 4
The formula is
Answer:
No
Step-by-step explanation:
To find out, all we need to do is plug in 9999 into the sequence.

By completing the square, we get
. 1001 is not a perfect square, which means that 9999 is not in the sequence.
hope this helped! :)