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Aleksandr [31]
3 years ago
15

A sled of mass 15 kg slides across the ground with a friction force of 80.85 N. What is k between the sled and the ground?

Physics
2 answers:
Dvinal [7]3 years ago
8 0
The expression for the frictional force between the sled and the ground is:
F=k m g
where k is the coefficient of friction, m is the mass of the object and g=9.81 m/s^2 is the gravitational acceleration.

The friction force in our problem is F=80.85 N. The mass of the object is m=15 kg. Re-arranging the formula, we can find the value of k:
k= \frac{F}{mg}= \frac{80.85 N}{(15 kg)(9.81 m/s^2)}=0.55
ki77a [65]3 years ago
3 0

0.55 is correct - APEX

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PLEASE HELP
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3.675 m

Explanation:

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X-direction     | Y-direction

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