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Aleksandr [31]
3 years ago
15

A sled of mass 15 kg slides across the ground with a friction force of 80.85 N. What is k between the sled and the ground?

Physics
2 answers:
Dvinal [7]3 years ago
8 0
The expression for the frictional force between the sled and the ground is:
F=k m g
where k is the coefficient of friction, m is the mass of the object and g=9.81 m/s^2 is the gravitational acceleration.

The friction force in our problem is F=80.85 N. The mass of the object is m=15 kg. Re-arranging the formula, we can find the value of k:
k= \frac{F}{mg}= \frac{80.85 N}{(15 kg)(9.81 m/s^2)}=0.55
ki77a [65]3 years ago
3 0

0.55 is correct - APEX

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Rus_ich [418]
A) The answer is 11.53 m/s

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KEf = KEi + PEi

Kinetic energy depends on mass (m) and velocity (v)
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b) The answer is 6.78 m

The kinetic energy at the bottom (KE) is equal to the potential energy at the highest point (PE)
KE = PE

Kinetic energy depends on mass (m) and velocity (v)
KE = 1/2 m * v²

Potential energy depends on mass (m), acceleration (a), and height (h):
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KE = PE
1/2 m * v² = m * a * h

Divide both sides by m:
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1/2 * 11.53² = 9.8 * h
1/2 * 132.94 = 9.8 * h
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h = 66.47 / 9.8
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