Answer:
v = 135.13 mph
Explanation:
Given that,
The race car was moving for 3.7 hours and during that time it traveled a distance of 500 miles south.
We need to find the speed of the car.
We know that,
Speed = distance/time
So,
So, the speed of the car is equal to 135.13 mph.
Answer:
Fₓ = 21.9 kN
Fᵧ = 84.3 kN
T = 32.7 kN
Explanation:
Draw a free body diagram (assuming the weight of the structure is included in the 60 kN force).
There are vertical and horizontal reaction forces at A (Fᵧ and Fₓ), and a tension force T at B pulling down along the rope.
The length of BC is √(2.7² + 3²) = √16.29. Using similar triangles, the vertical and horizontal components of the tension force are:
Tᵧ = 3 T / √16.29 ≈ 0.743 T
Tₓ = 2.7 T / √16.29 ≈ 0.669 T
Sum of moments about A in the counterclockwise direction:
∑τ = Iα
Tᵧ (1 m) + Tₓ (3 m) − 60 kN (1 m) − 30 kNm = 0
Tᵧ + 3 Tₓ = 90 kN
0.743 T + 3 (0.669 T) = 90 kN
2.750 T = 90 kN
T = 32.7 kN
Sum of forces in the +x direction:
∑F = ma
Fₓ − Tₓ = 0
Fₓ = Tₓ
Fₓ = 0.669 T
Fₓ = 21.9 kN
Sum of forces in the +y direction:
∑F = ma
Fᵧ − Tᵧ − 60 kN= 0
Fᵧ = Tᵧ + 60 kN
Fᵧ = 0.743 T + 60 kN
Fᵧ = 84.3 kN
Answer:
A projectile is launched from and returns to ground level, as the figure shows. There is no air resistance. The horizontal range of the projectile is measured to be R= 167 m, and the horizontal component of the launch velocity is v0x = 22.0 m/s. Find the vertical component v0y of the projectile
Explanation:
bhai figure kaha hai
The net force in the tug of war which is shown in the picture provided will be 0N.
<h3>What is a Force?</h3>
This is defined as the power exerted on a body and the unit of Force is referred to as Newton.
In the tug of war, the net force is gotten by summing up all the forces.
–190N + 10N –10N + 190N = 0N.
Therefore the net force is 0N.
Read more about Force here brainly.com/question/12970081
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Answer:
ive never done this befor but i think its 36 times aroud earth a day
Explanation:
384400/400=961
961% of 27 days is 40minuets
1440/40=36